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Oxana [17]
3 years ago
14

(50 points) Could someone help me with this? Part A: Solve –mk – 90 > 85 for m. Part B: Solve 3c – 5f = 55 for f. Show your w

ork for both but please don't make it too complicated.
Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0

A:

-mk - 90 > 85

-mk - 90 + 90 > 85 + 90

-mk > 175

-mk / k > 175 / k

-m > 175/k

-m * -1 < 175/k * -1

m < -175/k


Part B:

3c - 5f = 55

3c - 5f - 3c = 55 - 3c

-5f = 55 - 3c

-5f/5 = (55 - 3c) / 5

-f = 55/5 - 3c/5



labwork [276]3 years ago
3 0

Answer:

90>85

Step-by-step explanation:

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Lazurus Steel Corporation produces iron rods that are supposed to be 36 inches long. The machine that makes these rods does not
Igoryamba

Answer:

Step-by-step explanation:

We would construct a confidence interval.

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Since the sample size is large and the population standard deviation is known, we would use the following formula and determine the z score from the normal distribution table.

Margin of error = z × σ/√n

Where

σ = population standard Deviation

n = number of samples

From the information given

x = 36.02 inches

σ = 0.1 inches

n = 40

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.005 = 0.995

The z score corresponding to the area on the z table is 2.58. Thus, confidence level of 99% is 2.58

Margin of error = 2.58 × 0.1/√40 = 0.041

Confidence interval = 36.02 ± 0.041

The lower end of the confidence interval is

36.02 - 0.041 = 35.979 inches

The upper end of the confidence interval is

36.02 - 0.041 = 36.061 inches

Since 36.061 > 36.05, then we would conclude that the machine needs an adjustment.

The formula used is

Confidence interval =

Sample mean ± z × σ/√n

7 0
3 years ago
What directed number is suggested by the statement "I gained 3 pounds "?​
sammy [17]

Answer:

The directed number suggested is +3.

Step-by-step explanation:

A directed number is one that has either a positive or negative sign, so that it could be easily located on the number line. Thus, the sign shows the direction of the number. Examples are: -2, -1, +5, +6 etc.

From the given question, let the initial weight be represented by W, then:

I gained 3 pounds implies at that; 3 pounds was added to my initial weight. Thus, my present weight is my initial weight + 3 pounds.

i.e I gained 3 pounds ⇒ W + 3

So that the directed number suggested by the statement is +3.

7 0
3 years ago
One side of a right triangle is 8 cm shorter than the hypotenuse and 7 cm shorter than the third side. Find the lengths of the s
Reptile [31]

Answer:

5 cm

Step-by-step explanation:

Let the shorter side be a, longer side be b, hypotenuse be c

By Pythagorean theorem:

a² + b² = c²

a² + (a + 7)² = (a + 8)²

a² + a² + 14a + 49 = a² + 16a + 64

a² - 2a - 15 = 0

a² + 3a - 5a - 15 = 0

a(a + 3) - 5(a + 3) = 0

(a + 3)(a - 5) = 0

a = -3 or a = 5

Because a is a side length and is a positive number

a = 5

7 0
3 years ago
Differential cos^2x dy/dx =e^y-tanx​
gulaghasi [49]

Answer:

y=t−1+ce

−t

where t=tanx.

Given, cos

2

x

dx

dy

+y=tanx

⇒

dx

dy

+ysec

2

x=tanxsec

2

x ....(1)

Here P=sec

2

x⇒∫PdP=∫sec

2

xdx=tanx

∴I.F.=e

tanx

Multiplying (1) by I.F. we get

e

tanx

dx

dy

+e

tanx

ysec

2

x=e

tanx

tanxsec

2

x

Integrating both sides, we get

ye

tanx

=∫e

tanx

.tanxsec

2

xdx

Put tanx=t⇒sec

2

xdx=dt

∴ye

t

=∫te

t

dt=e

t

(t−1)+c

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8 0
2 years ago
Use an algebraic approach to solve the problem.
qaws [65]

Answer:

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

Step-by-step explanation:

Use the formula for the mean: sum of elements / number of elements

Let x represent her first exam score.

Her second exam score can be represented by x + 11, since it was 11 points better than her first.

Her third exam score can be represented by (x + 11) + 5, since it was 5 points better than her second.

Plug in all of these expressions into the mean formula. Plug in 87 as the mean, and plug in 3 as the number of elements (since there are 3 scores):

mean = sum of elements / number of elements

87 =  ( (x) + (x + 11) + (x + 11) + 5 ) / 3

Add like terms and solve for x:

87 = (3x + 27) / 3

261 = 3x + 27

234 = 3x

78 = x

So, her first score was a 78.

Find her second score by adding 11 to this:

78 + 11 = 89

Find her third score by adding 5 to the second score:

89 + 5 = 94

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

6 0
3 years ago
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