Answer:
The induced emf 1.43 s after the circuit is closed is 4.19 V
Explanation:
The current equation in LR circuit is :
.....(1)
Here I is current, V is source voltage, R is resistance, L is inductance and t is time.
The induced emf is determine by the equation :
Differentiating equation (1) with respect to time and put in above equation.
Substitute 6.05 volts for V, 0.655 Ω for R, 2.55 H for L and 1.43 s for t in the above equation.
This question deals with the acceleration due to gravity on the surface of the planet. The value of the acceleration due to gravity on the surface of two planets, that is Earth and on the surface of another planet are compared to find out the relation between the radii of both planets, provided their masses are the same.
The correct option for the radius of the new planet is "Option 3: Square Root of 3 R"
The value of the acceleration due to gravity on the surface of a planet is given by the following formula:
----------- eqn(1)
where,
g = acceleration due to gravity on Earth
G = Universal Gravitational Constant
M = mass of the Earth
R = Radius of the Earth
Now, the same formula for the acceleration due to gravity on the surface of the other planet can be written as follows:
------------- eqn(2)
where,
g' = acceleration due to gravity on the new planet
G = Universal Gravitational Constant
M' = mass of the new planet
R' = Radius of the new planet
According to the given condition, the new planet has the same mass as the Earth's mass but the acceleration due to gravity on the surface of the new planet is one-third of the acceleration due to gravity on the surface of Earth.
using eqn (1) and eqn (2):
Hence, the radius of the new planet is found to be equal to the square root of 3 times the radius of the Earth (Square Root of 3 R).
Learn more about acceleration due to gravity on the surface of a planet here:
Hi there!
To calculate the tension, we must calculate the acceleration of the system.
Begin with a summation of forces:
∑F = -M₁gsinФ + T - T + M₂g
Simplify and solve for acceleration: (Tensions cancel out)
Plug in values. Let g = 10 m/s²
Now, to find tension, let's sum up the forces acting on ONE block. For simplicity, we can look at the hanging block:
∑F = -T + W
ma = -T + W
Rearrange to solve for T:
T = W - ma
We know the acceleration, so plug in the values:
T = (8)(10) - (8)(5.91) = 32.73 N