All categories

3 years ago

In the past, the intensity of the Earth's magnetic field was _____. A. greater B. weaker C. same D. evidence is inconclusive?

Physics

2 answers:

Margarita [4]3 years ago

7 0

I'd say a because it says it's magnetic field as decreased by 10% in the last century

riadik2000 [5.3K]3 years ago

7 0

I'm sure A is the right answer

You might be interested in

Convert the following:

Alika [10]

Explanation:

A) 1 kg = 1000g

2500kg = 2500000g

B 1 hour = 3600 sec

335 hour = 1206000sec

C 1day = 24 hours

1 hour = 3600 sec

24 hours = 86400sec

5 0

3 years ago

Read 2 more answers

Consider a container of oxygen gas at a temperature of 23°C that is 1.00 m tall. Compare the gravitational potential energy of a

Sergio039 [100]

Answer:

Yes, it is reasonable to neglect it.

Explanation:

Hello,

In this case, a single molecule of oxygen weights 32 g (diatomic oxygen) thus, the mass of kilograms is (consider Avogadro's number):

$m=1molec*\frac{1mol}{6.022x10^{23}molec} *\frac{32g}{1mol}*\frac{1kg}{1000g}=5.31x10^{-26}kg$

After that, we compute the potential energy 1.00 m above the reference point:

$U=mhg=5.31x10^{-26}kg*1.00m*9.8\frac{m}{s^2}=5.2x10^{-25}J$

Then, we compute the average kinetic energy at the specified temperature:

$K=\frac{3}{2}\frac{R}{Na}T$

Whereas $N_A$ stands for the Avogadro's number for which we have:

$K=\frac{3}{2} \frac{8.314\frac{J}{mol*K}}{6.022x10^{23}/mol}*(23+273)K\\ \\K=6.13x10^{-21}J$

In such a way, since the average kinetic energy energy is about 12000 times higher than the potential energy, it turns out reasonable to neglect the potential energy.

Regards.

8 0

3 years ago

What circumstance would allow an officer to search a home even if they didn’t have a warrant?

Ipatiy [6.2K]

Answer:

Explanation:

The officer would have had permission regardless of anything else, kind of like letting someone into your house.

5 0

3 years ago

Suppose you have a pendulum clock that keeps correct time on Earth (acceleration due to

vekshin1

Answer:

dont know because I am a student lol

8 0

2 years ago

Read 2 more answers

Electric charge is distributed over the disk x2 + y2 ≤ 4 so that the charge density at (x, y) is rho(x, y) = 4x + 4y + 4x2 + 4y2

maw [93]

Answer:

Q=185.84C

Explanation:

We have to take into account the integral

$Q=\int \rho dV$

In this case we have a superficial density in coordinate system.

Hence, we have for R: x2 + y2 ≤ 4

$Q=\int_{-2}^2\int_{-\sqrt{4-x^2}}^{\sqrt{4-x^2}}\rho dydx$

but, for symmetry:

$Q=4\int_0^2\int_0^{\sqrt{4-x^2}}\rho dydx\\\\Q=4\int_0^2\int_0^{\sqrt{4-x^2}}(4x+4y+4x^2+4y^2) dydx\\\\Q=4\int_0^{2}[4x\sqrt{4-x^2}+2(4-x^2)+4x^2\sqrt{4-x^2}+\frac{4}{3}(4-x^2)^{3/2}]dx\\\\Q=4[46.46]=185.84C$

HOPE THIS HELPS!!

8 0

3 years ago