Answer:
Acids break down fabrics and can cause burns if the acids are strong.
Explanation:
A protective apron or lab coat is important when working with acids because acids break down fabrics and can cause burns if the acids are strong.
- An acid is a substance that interacts with water to produce excess hydroxonium ions in an aqueous solution.
- A strong acid ionizes completely in solution.
- When they come in contact with a fabric, they break them down violently.
- So, if they come in contact with the skin, it causes a violent break down of body tissues.
- The apron acts a protective layer.
Angular acceleration = (change in angular speed) / (time for the change)
change in angular speed = (zero - 2,600 RPM) = -2,600 RPM
time for the change = 10 sec
Angular acceleration = -2600 RPM / 10 sec = -260 rev / min-sec
(-260 rev/min-sec) x (1 min / 60 sec) = <em>-(4 1/3) rev / sec²</em>
Since the acceleration is negative, the motor is slowing down.
You might call that a 'deceleration' of (4 1/3) rev/sec² .
The average speed is 1/2(2,600 + 0) = 1,300 rev/min = (21 2/3) rev/sec.
Number of revs = (average speed) x (time) = (21 2/3) x (10sec) = <em>(216 2/3) revs</em>
Answer:
Explanation:
Newton’s Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass (object). Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass.
Answer:
a charge Q is transferred from an initially uncharged
Explanation:
Hope this helps!
Answer with Explanation:
We are given that
![D_1=0.15mGy](https://tex.z-dn.net/?f=D_1%3D0.15mGy)
![D_2=0.22mGy](https://tex.z-dn.net/?f=D_2%3D0.22mGy)
![Q_1=6](https://tex.z-dn.net/?f=Q_1%3D6)
![Q_2=10](https://tex.z-dn.net/?f=Q_2%3D10)
a.We have to find the total dose
Total dose=![D=D_1+D_2](https://tex.z-dn.net/?f=D%3DD_1%2BD_2)
Using the formula then, we get
![D=0.15+0.22](https://tex.z-dn.net/?f=D%3D0.15%2B0.22)
![D=0.37mGy](https://tex.z-dn.net/?f=D%3D0.37mGy)
b.We have to find the total dose equivalent
Total dose equivalent=H=![D_1Q_1+D_2Q_2](https://tex.z-dn.net/?f=D_1Q_1%2BD_2Q_2)
Using the formula
![H=0.15(6)+0.22(10)](https://tex.z-dn.net/?f=H%3D0.15%286%29%2B0.22%2810%29)
H=3.1mSv