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Dimas [21]
3 years ago
15

A carpenter added a diagonal brace to a gate. The gate is 80 inches wide and 60 inches tall. How long is the brace?

Mathematics
1 answer:
tester [92]3 years ago
4 0
<span>We can use the Pythagorean theorem to solve for the diagonal (hypotenuse) length of the gate. This theorem states that a^2 + b^2 = c^2 where a and b are the leg lengths and c is the hypotenuse length. In this case, 80^2 + 60^2 = 6400 + 3600 = 10,000 = c^2. Taking the square root, we see that the length of the brace is 100 inches (thus making the gate a standard 3-4-5 right triangle).</span>
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<h3>Answer:  29</h3>

=================================

Work Shown:

Solve the second equation for f(b)

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f(b) = 28/2

f(b) = 14

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Plug in x = b and solve for b

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f(b) = 3b-1 ... replace every x with b

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Step-by-step explanation:

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Please answer this..
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STEP 1

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STEP 3

STEP 4

Pulling out like terms

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Trying to factor a multi variable polynomial :

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Try to factor this multi-variable trinomial using trial and error

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