A carpenter added a diagonal brace to a gate. The gate is 80 inches wide and 60 inches tall. How long is the brace?

1 answer:

4 0

<span>We can use the Pythagorean theorem to solve for the diagonal (hypotenuse) length of the gate. This theorem states that a^2 + b^2 = c^2 where a and b are the leg lengths and c is the hypotenuse length. In this case, 80^2 + 60^2 = 6400 + 3600 = 10,000 = c^2. Taking the square root, we see that the length of the brace is 100 inches (thus making the gate a standard 3-4-5 right triangle).</span>

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x=14

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If the square from GAI are 6 cm, then the other half of the triangle is also 6 inches long. Because it is not an even sided triangle, all the sides shouldnt be the same size. If you multiply 6 by 2 you get 12. 7 times 6 is 42. 42 divided by 3 is 14. The value of X should be 14.

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