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Dimas [21]
3 years ago
15

A carpenter added a diagonal brace to a gate. The gate is 80 inches wide and 60 inches tall. How long is the brace?

Mathematics
1 answer:
tester [92]3 years ago
4 0
<span>We can use the Pythagorean theorem to solve for the diagonal (hypotenuse) length of the gate. This theorem states that a^2 + b^2 = c^2 where a and b are the leg lengths and c is the hypotenuse length. In this case, 80^2 + 60^2 = 6400 + 3600 = 10,000 = c^2. Taking the square root, we see that the length of the brace is 100 inches (thus making the gate a standard 3-4-5 right triangle).</span>
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Answer:

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equation: y=0.05x+45.5

graph: attached below

Step-by-step explanation:

We can write this in slope-intercept form, or y=mx+b. Since x is defined as the #of text messages, and 0.05 is the cost of a text message, 0.05 will be m. 45.5 is the base price, or the y-intercept, so it will be b.

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Step-by-step explanation:

Since a square has 4 sides and they are all equal, you want to divide 47 by 4.

You will get 11.75 inches per side.

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