What needs to be done first is to add up females and males that have passed.
42 + 14 = 56
so out of 56 students who passed 42 females passed 42/56 = 3/4 = 0.75
out of 56 students who passed, 14 males passed which turns into 14/56 = 1/4 = 0.25
check work; 0.75 + 0.25 = 1.00
NOW WE ARE DOING FAILS.
15 + 5 = 20
so out of 20 students who failed, 15 females failed so it turns into 15/20 = 3/4 = 0.75
out of 20 students who failed, 5 males failed. 5/20 = 1/4 = 0.25
check work; 0.75 + 0.25 = 1.00
i hope this helped! :)
Answer:
p = 2 and q = 2
Step-by-step explanation:
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Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
There are 4 per row.
12 divided by 3 = 4.
Answer:
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