1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vova2212 [387]
3 years ago
12

An isotope undergoes radioactive decay by emitting radiation that has no mass. What other characteristic does the radiation have

?
a. some shielding required
b. positive or negative charge
c. low penetrating power
d. no charge
Chemistry
2 answers:
lbvjy [14]3 years ago
8 0
The correct answer is D) No charge
Oksi-84 [34.3K]3 years ago
6 0
The right answer for the question that is being asked and shown above is that: "b. positive or negative charge" An isotope undergoes radioactive decay by emitting radiation that has no mass. The other characteristic does the radiation have is that b. positive or negative charge

You might be interested in
Compounds mixtures and elements ​
Jlenok [28]

Compound - made out of two or more types of elements chemically combined

Mixture - two or more substances in which the substances retain their identity

Element - simplest form of matter that is present by itself

8 0
4 years ago
The mass of an electron is
stealth61 [152]
The mass of an electron is:
 0.00054386734 or 9.1 x <span>10^-31 kg</span><span>.
</span>Good Luck!!
4 0
3 years ago
Read 2 more answers
The eighth planet from the sun the outermost of gas planets please help
Step2247 [10]
Answer: Neptune
Explanation: think about the phrase
My Very Eager Mother Just Served Us Nachos

(Mercury, Venus, earth, Mars, Jupiter, Saturn, Uranus, Neptune)
3 0
3 years ago
if the theoretical yield of a acetic acide in a certain experiment is 21.4 grams and the actual yield is 19.1 grams, what is the
Shtirlitz [24]

Answer:

89.2 %

Explanation:

Percent yield = (Yield produced / Theoretical yield) . 100

(19.1 g / 21.4 g) . 100 = 89.2 %

7 0
4 years ago
Rank the following molecules from highest to lowest boiling point: CO2, H2S, NaF, NH3. Explain your ranking using IMF’s.
qaws [65]

Answer:

NaF>NH3>H2S>CO2

Explanation:

The boiling point of a substance depends on the magnitude of electronegativity difference and the type of bond between the atoms of the compound in question.

NaF is an ionic substance. Ionic substances have a high melting and boiling point due to the fact that the ionic lattice contains a large number of ions. This means that a lot of energy is usually required to overcome this ion-ion interaction therefore ionic compounds usually have high melting and boiling points.

Nitrogen is more electronegative than sulphur hence NH3 is more polar than H2S and consequently NH3 has a higher boiling point than H2S due to stronger dipole-dipole interaction.

CO2 is a nonpolar molecule hence it has the lowest boiling point. Only weak dispersion forces exist in CO2.

8 0
3 years ago
Other questions:
  • 4. 200 mL of a 5.6M solution to BaCl_2 have 750 mL of water added to it. What is the new concentration?
    10·1 answer
  • Potassium hydrogen phthalate is often used to standardize solutions of strong bases. Highly pure samples of this solid weak acid
    10·1 answer
  • To produce 3.00 L of a 1.90 M solution of sodium hydroxide (NaOH), how many grams of sodium hydroxide must be dissolved?
    11·1 answer
  • What is the gasoline doing to our environment?
    14·1 answer
  • Give an example of a cause and effect relationship.
    14·1 answer
  • Does grass have cells
    6·1 answer
  • Which of the following is true about Avogadro’s number? *
    15·2 answers
  • What happens when you continue to add a solute to an already saturated solution
    9·1 answer
  • Use the drop down menus to answer the questions. In what type of plate boundary did subduction occur? In what type of plate boun
    7·2 answers
  • Can someone tell me a summary of volcanoes and plate tectonics? (Please quickly!)
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!