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Ann [662]
3 years ago
15

And electromagnet is in temporary magnet made by Coiling wire around an iron core which becomes a magnet win and electric curren

t flows through the wire how could a strength of an electromagnet be increase
Physics
1 answer:
Bad White [126]3 years ago
3 0

Answer:

We can increase the strength by increasing current in the wire or increasing the number of turns of the coil around an iron core .

Explanation:

The magnetic strength due to current carrying conductor carrying current I and having N number of turns is given by

      B = \mu _{0}\times N\times I

\mu_{O} is vacuum permeability .and its value is equal to 4\pi\times10^{-7} \frac{H}{m}

.so from the above equation we can see that magnetic strength is directly proportional to the current through wire and no. of turns .

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Current Flow and Ohm's Law

Ohm's law is the most important, basic law of electricity. It defines the relationship between the three fundamental electrical quantities: current, voltage, and resistance. When a voltage is applied to a circuit containing only resistive elements (i.e. no coils), current flows according to Ohm's Law, which is shown below.

I = V / R 

Where: 

I =

Electrical Current (Amperes)

V =

Voltage (Voltage)

R =

Resistance (Ohms)

    

Ohm's law states that the electrical current (I) flowing in an circuit is proportional to the voltage (V) and inversely proportional to the resistance (R). Therefore, if the voltage is increased, the current will increase provided the resistance of the circuit does not change. Similarly, increasing the resistance of the circuit will lower the current flow if the voltage is not changed. The formula can be reorganized so that the relationship can easily be seen for all of the three variables.

The Java applet below allows the user to vary each of these three parameters in Ohm's Law and see the effect on the other two parameters. Values may be input into the dialog boxes, or the resistance and voltage may also be varied by moving the arrows in the applet. Current and voltage are shown as they would be displayed on an oscilloscope with the X-axis being time and the Y-axis being the amplitude of the current or voltage. Ohm's Law is valid for both direct current (DC) and alternating current (AC). Note that in AC circuits consisting of purely resistive elements, the current and voltage are always in phase with each other.

Exercise: Use the interactive applet below to investigate the relationship of the variables in Ohm's law. Vary the voltage in the circuit by clicking and dragging the head of the arrow, which is marked with the V. The resistance in the circuit can be increased by dragging the arrow head under the variable resister, which is marked R. Please note that the vertical scale of the oscilloscope screen automatically adjusts to reflect the value of the current.

See what happens to the voltage and current as the resistance in the circuit is increased. What happens if there is not enough resistance in a circuit? If the resistance is increased, what must happen in order to maintain the same level of current flow?


4 0
4 years ago
What is the ratio of the kinetic energy of this satellite to its potential energy?
In-s [12.5K]
Tu no mete cabra saramambiche

6 0
3 years ago
A 1.2-kg mass is projected from ground level with a velocity of 31.3 m/s at some unknown angle above the horizontal. A short tim
My name is Ann [436]

Answer:

The kinetic energy will be "399.65 J".

Explanation:

Given:

Mass,

m = 1.2 kg

Velocity,

v = 31.3 m/s

The total energy of mass will be:

⇒ E=K+U

or,

⇒ E=.5mv^2+mgh

By putting the values, we get

        =.5(1.2)(31.3)^2+0

        =0.6\times 979.69+0

        =587.81 \ J

Since,

The system's total energy is unchanged, then

⇒ E=K+U

or,

⇒ E=K+mgh

   587.81=K+1.2(9.8)(16)

   587.81=K+188.16

          K=587.81-188.16                

               =399.65 \ J

8 0
4 years ago
In the nucleus of an atom, there are 18 protons and 20 neutrons. What are the atomic number and mass number of this isotope?
Musya8 [376]
Atomic number is 18 and mass number is 38.
8 0
3 years ago
Read 2 more answers
How much mass does the sun lose through nuclear fusion per second?
Mekhanik [1.2K]

Answer:

1.10^6 kg of mass per second

Explanation:

All energy lost by the sun comes from nuclear fusion.

Sun loses energy at 2.5*10^{19}J per hour, that is 9*10^{22}J/s

To find the mass lost by the sun in liberation of energy you use the famous Einstein's equation:

E=mc^2\\\\m=\frac{E}{c^2}=\frac{9*10^{22}}{(3*10^{8}m/s)^2}=1*10^6kg

hence, the sun liberates 1.10^6 kg of mass per second

3 0
4 years ago
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