Ask question

Ask question

All categories

3 years ago

11

Consider two closed systems A and B. System A contains 3000 kJ of thermal energy at 20°C, whereas system B contains 200 kJ of th

ermal energy at 50°C. Now the systems are brought into contact with each other. Will the heat transfer occur from system A to system B?

1 answer:

Soloha48 [4]3 years ago

4 0

No because they’re closed.

You might be interested in

400 Kelvin to degrees Celsius

sineoko [7]

Answer:

400-273

127° C

I hope it's helps you

5 0

3 years ago

Read 2 more answers

When organic polymers joined together on early earth, they formed ______? Protons Protobionts Monomers Plankton

Sidana [21]

I think the answer would be protons

4 0

3 years ago

Read 2 more answers

Suppose an oven's radiation wavelength is 0.125 m. a container with 350.00 g of water was placed in the oven, and the temperatur

ivann1987 [24]

The heat (energy) needed to raise the temperature of the water is given by
$Q=m C_S (T_f - T_i)=(350.0 g)(4.18 J/gC)(80C-20C)=87780 J$

The wavelength of the radiation of the oven is $\lambda=0.125 m$ , so the energy of a single photon of this radiation is
$E=h \frac{c}{\lambda}=(6.6 \cdot 10^{-34}J) \frac{3\cdot 10^8 m/s}{0.125 m}=1.6 \cdot 10^{-24} J$

So, the number of photons required to heat the water is the total energy absorbed by the water divided by the energy of a single photon:
$N= \frac{Q}{E}= \frac{87780 J}{1.6\cdot 10^{-24}J}= 5.5 \cdot 10^{28}$ photons

8 0

3 years ago

Which of these statements partially defines law?

xz_007 [3.2K]

Answer: I dont see the option choices

Explanation:

5 0

3 years ago

A tennis ball connected to a string is spun around in a vertical, circular path at a uniform speed. The ball has a mass m = 0.16

ycow [4]

We assign the variables: T as tension and x the angle of the string
The <span>centripetal acceleration is expressed as v²/r=4.87²/0.9 and (0.163x4.87²)/0.9 = </span><span>T+0.163gcosx, giving T=(0.163x4.87²)/0.9 – 0.163x9.8cosx.
</span>
<span>(1)At the bottom of the circle x=π and T=(0.163x4.87²)/0.9 – .163*9.8cosπ=5.893N. </span>
<span>(2)Here x=π/2 and T=(0.163x4.87²)/0.9 – 0.163x9.8cosπ/2=4.295N. </span>
<span>(3)Here x=0 and T=(0.163x4.87²)/0.9 – 0.163x9.8cos0=2.698N. </span>
<span>(4)We have T=(0.163v²)/0.9 – 0.163x9.8cosx.

</span><span>This minimum v is obtained when T=0 </span><span>and v verifies (0.163xv²)/0.9 – 0.163x9.8=0, resulting to v=2.970 m/s.</span>

4 0

3 years ago

Read 2 more answers