Work = force * distance
and newton*meters = Joule
In this case, work = 250N*50m = 12500 J
So the answer is D) 12,500 J
Capacitor in series with a 100Ω resistor and a 18.0 mH inductor will give a resonance frequency of 1000 Hz is 1.38F
Resonance Frequency of a combination of Series LCR circuit is the frequency at which resonance is achieved in a circuit.
Resonance Frequency of a combination of Series LCR circuit is given by:
f = 1 / 2π
where, f is the resonance Resonance Frequency of a combination of Series LCR circuit
L is the Inductance of the inductor
C is the capacitance of the capacitor
Given,
f = 1000Hz
L = 18.0 mH = 0.018H
R = 100Ω
C = ?
On substituting the values in the above-mentioned formula:
1000 = 1 / 2π
2π = 0.001
On solving, C = 1.38 F
Hence, the capacitance of the given capacitor is 1.38F.
Learn more about Resonant frequency here, brainly.com/question/13040523
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Answer:
3100
Explanation:
Because no extra force is implied for it to exalarate