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inessss [21]
4 years ago
9

Graph the function. Give domain and range in interval form.

Mathematics
1 answer:
sertanlavr [38]4 years ago
6 0

Answer:

Domain: all real values of x

Range: all real values of y

Translation depends on the parent function

If the first function was:

y = cuberoot(x)

Then translation is:

Vertical translation 1 unit downwards

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What is the other name for data preparation stage of knowledge discovery process.
dmitriy555 [2]

ETL is the other name for 'Data Preparation' stage of knowledge discovery process.

Explanation:

  • ETL can be defined as a technique for extracting data from various RDBMS systems.
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2 years ago
What is 13.026 in expanded form using fractions for the decimal places
Crank
10 + 3 + 2/100 + 6/1000

hope it helps!
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3 years ago
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Kim works as a server in a restaurant. She is serving the table where a group of her friends are eating. Her friends always tip
Lisa [10]

if the bill was $23.60, and the tip was 15%, kim will earn $3.54. the overall total of the meal would be $27.14 :)

Anwser will be $3.54

15% = .15 ( to convert percent to decimal, change the % to . and move the decimal two places to the left)

23.60 * .15 = 3.54

8 0
3 years ago
Which ratio is equivalent to 4 : 28?
rusak2 [61]
4 : 28 is the same as 4/28 

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The answer is C
3 0
3 years ago
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At the time of her​ grandson's birth, a grandmother deposits $ 3000 in an account that pays 3 % compounded monthly. What will be
GaryK [48]

Answer:

The value of the account will be $5,628

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=21\ years\\ P=\$3,000\\ r=3\%=3/100=0.03\\n=12  

substitute in the formula above  

A=3,000(1+\frac{0.03}{12})^{12*21}  

A=3,000(1.0025)^{252}  

A=\$5,628  

therefore

The value of the account will be $5,628

5 0
4 years ago
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