Do you have a picture of it
A quadratic equation has the general form of:
<span>
y=ax² + bx + c
</span><span>
It can be converted to the vertex form in order to determine the vertex of the parabola. It has the standard form of:
</span><span>
y = a(x+h)² - k
</span><span>
where h, k are the vertex points.
</span><span>
y=-2x^2 + 2x+ 2
</span><span>y=-2(x^2 - x) + 2
</span><span>y + 1/4 = -2 (x^2 -x +1/4) + 2
</span><span>y = -2 (x - 1/2)^2 + 7/4
</span><span>
Therefore, the vertex is (-1/2, -7/4)
</span><span>
at x = 6, y = -58</span>
