The expansion diameters of the steel cylinder is 0.3mm
The expansion stress on the steel cylinder is 150MPa
<h3>Diameter of thin walled cylinder </h3>
t = Dp / 2s
low pressure cylinder of cast iron used for certain engine
t = Dp / 2500 + 0.3
wall thickness = 0.3 mm
p = internal pressure
d = inside diameter of cylinder
t = wall thikness
s = allowable tensile stress
<h3>The stress of the cylinder is</h3>
The pressure in a thin walled tube with diameter 0.3 m and thickness 0.001 m is 1000 kPa (10 bar).
The hoop stress can be calculated
σh = (1000 kPa) (0.3 m) / (2 (0.001 m))
= 150000 kPa
= 150 MPa
Hence , The diameter of the thin walled cylinder is 0.3mm
The stress of the thin walled cylinder is 150 MPa
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Answer:
9.28 g/L
Explanation:
We will be using the ideal gas law to solve this problem:
PV = nRT where P is the pressure (atm)
V is the volume (L)
R is the gas constant 0.08205 Latm/Kmol
T is the temperature (K)
n is the number of moles
The number of moles is the mass divided by the molecular weight, and from here we can solve for the density. (Note here we use the atomic weight of radon since its is a monoatomic noble gas)
PV = m/AW RT ⇒ P = (m/V ) RT/AW ⇒ P AW /RT =D
0.950 atm x 222.0 g/mol / [( 0.08205 Latm/Kmol ) x 277 K ] = D
9.28 g/L = D
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3. Base are used in </span><span>Used in ammonia, Alka-Seltzer, and dish soap
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4. </span><span>TRUE . Simple devices lower the required input force.
5. FALSE. It's the opposite.</span>