We know that the element Z = 119 would be placed right below the Fr, in the column of the alcaline metals.
We also know that the trend in the electronegativity is to decrease when you go up-down ia group.
The known electronegativities of the elements of this group are:
Li: 0.98
Na: 0.93
K: 0.82
Rb: 0.82
Cs: 0.79
Fr: 0.70
Then the hypotetical element Z = 119 would probably have an electronegativity slightly below 0.70, for sure in the range 0.60 - 0.70.
Sulfur is an element of the periodic table that is not considered a metalloid.
<h3>What is sulfur?</h3>
Sulfur is a chemical element of the periodic table that has the following characteristics:
- Atomic number 16
- S symbol
- Sulfur is classified as a nonmetal
- It has a yellow color
<h3>What are metalloids?</h3>
Metalloids are a set of chemical elements of the periodic table that are characterized by having an intermediate behavior between metals and non-metals, in terms of ionization energies and binding properties.
It is not easy to distinguish them from true metals. They conduct electrical current better than non-metals, but they are not good conductors like metals. In addition, they are usually very varied in their shape and coloration.
The list of metalloids includes the following elements:
- Boron (B)
- Silicon (Si)
- Germanium (Ge)
- Arsenic (As)
- Antimony (Sb)
- Tellurium (Te)
- Polonium (Po)
Learn more about periodic table in: brainly.com/question/11155928
Answer:
The required volume of hexane is 0.66245 Liters.
Explanation:
Volume of octane = v=1.0 L=
Density of octane= d = 
Mass of octane ,m= 
Moles of octane =
Mole percentage of Hexane = 45%
Mole percentage of octane = 100% - 45% = 55%

Total moles = 11.212 mol
Moles of hexane :

Moles of hexane = 5.0454 mol
Mass of 5.0454 moles of hexane,M = 5.0454 mol × 86 g/mol=433.9044 g
Density of the hexane,D = 
Volume of hexane = V

(1 cm^3= 0.001 L)
The required volume of hexane is 0.66245 Liters.
Answer:

Explanation:
Here, we want to convert J to cal
Mathematically:

Thus, to get our answer in cal, we divide the value given by 4.186
We have that as:
It requires a force in the direction opposite to the motion of the object for it to slow down.