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bixtya [17]
4 years ago
14

If m RST = 65, m QST = 2x, and m QSR = 3x - 10, what is the value of x?

Mathematics
1 answer:
DiKsa [7]4 years ago
6 0

Answer:

First, draw a quadrilateral figure QRST. Then, label angles RST, QST, and QSR.

Given:

mRST = 65

mQST = 2x

mQSR = 3x - 10

From the figure, angle RST is the sum of angles QST and QSR. Therefore:

mRST = mQST + mQSR

Substituting the values, the equation becomes:

65 = 2x + (3x -10)

Solve for x:

x = 15

Second awnser :

Upon drawing the triangles given, it may be observed that they share one common side, ST. Hence, m QSR is the sum of m RST and m QST. Mathematically,

                        3x - 10 = 65 + 2x

The value of x from the equation generated above is 75. Thus, the answer to the question above is 75.  

Hope i got it

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