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Jet001 [13]
3 years ago
9

There are 5 times as many males as females on the maths course at university. What fraction of the course are male? Give your an

swer in its simplest form.
Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
5 0

Answer:

5/6

Step-by-step explanation:

Let 'x' be number of females in the course

Number of males= 5x

total number of students= 5x+x

                                         = 6x

Fraction of male students= number of male students/total number of students

                                         = 5x/6x

                                         = 5/6

nordsb [41]3 years ago
5 0

Answer:

5/6.

Step-by-step explanation:

Given that M represents the Male and F represents the Female.

As per the statement:

There are 5 times as many males as females on the maths course at university.

Therefore M = 5F

Total number of person on the maths course = M + F = 5F+ F = 6F

Find the fraction of the course are male;

fraction of the course are male = Number of Males on the math course ÷ Total number of person on the course.

Substitute the given values we have;

fraction of the course are male = 5F/6F = 5/6

Hence, the fraction of the course are male is 5/6.

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A grocery store sells avocados for $1.25 each. The graph shows the cost for different numbers of avocados.
Aleksandr [31]
I don’t know if this is right or not so, sorry if it’s wrong ;-;

1,2,3,4,5 = independent

c=1.25a = neither

$1.25, $2.50, $3.75, $5.00, $6.25 = dependent

Number of avocados = independent

Cost of avocados = dependent

If this is right then I’ll put the explanation in the comments, again sorry if it isn’t.
5 0
2 years ago
Fermium-253 has a half life of three days. A sample contains 400 g. How long will it take for the sample to decay to 100 g?
NemiM [27]
After the first three days, the sample size will be half of the initial; therefore, 400g/2= 200g. However, it is asking how long will it take to decay to 100g, so we will take 200g/2= 100g, which will take another three days.  It will take 2 half-lives, which will encompass 6 days.
4 0
2 years ago
Tell whether the ordered pair is a solution of the given system. (-2,-4) {y=1/2x -3, y=-2x-8}
kompoz [17]

Answer:

The ordered pair (-2,\, -4) is indeed a solution to the system:

\left\lbrace\begin{aligned} & y = \frac{1}{2}\, x - 3 \\ & y = -2\, x - 8\end{aligned}\right..

Step-by-step explanation:

Consider a system of equations about variables x and y. An ordered pair (x_{0},\, y_{0}) (where x_{0} and y_{0} are constant) is a solution to that system if and only if all equations in that system hold after substituting in x = x_{0} and y = y_{0}.

For the system in this question, (-2,\, -4) would be a solution only if both equations in the system hold after replacing all x in equations of the system with (-2) and all y with (-4).

The \texttt{LHS} of the equation y = (1/2)\, x - 3 would become (-4). The \texttt{RHS} of that equation would become (1/2) \, (-2) - 3. The two sides are indeed equal.

Similarly, the \texttt{LHS} of the equation y = -2\, x - 8 would become (-4). The \texttt{RHS} of that equation would become (-2)\, (-2) - 8. The two sides are indeed equal.

Thus, x = (-2) and y = (-4) simultaneously satisfy both equations of the given system. Therefore, the ordered pair (-2,\, -4) would indeed be a solution to that system.

8 0
2 years ago
A dog jumps straight up. Y=-16t^2+20t models the motion of the dog, where "t" is the time in seconds and "y" is the height of th
alina1380 [7]

Answer:

Step-by-step explanation:

The motion of the dolphin is quadratic

i.e y=-16t²+20t

To get the maximum height the dolphin will reach

We need to find the point of inflexion. i.e dy/dt=0

dy/dt=-32t+20

Then set dy/dt=0

0=-32t+20

Then, -32t=-20

t=0.625

Let find d²y/dt²

d²y/dt²=-32. Since this is negative then the point t=0.625 is the maximum point the dolphin can reach

Then substitute t=0.625 into y

y=-16t²+20t

y=-16(0.625)²+20(0.625)

y=6.25ft

Then the maximum height the dolphin can reach is 6.25ft

Using discriminant

Formular method

y=-16t²+20t

So the dog height y<7

y=-16t²+20t <7

-16t²+20t-7<0

a=-16, b= 20. c=-7

t=(-b±√b²-4ac)/2a

Using the a, b and c direct for the discriminant

D=b²-4ac

D=20²-4×-16×-7

D=-48

Which is a complex number

Then the dolphin can reach the height

Then we need to model the D to be greater than 0

Therefore,

D>0

b²-4ac>0

We cannot do anything to a and b it is already given

a=-16, b=20

(20)²-4(-16c)>0

400+64c>0

64c>-400

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c>-6.25

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Therefore -c<6.25

So the dog height y<6.25

y=-16t²+20t <6.25

Therefore the maximum height is 6.25.

If it is greater than that then, we are going to have a complex root movement which is not possible for the dolphin .

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Jina wanted to study how the area of a rectangle changes with the length if it’s width is fixed. She computed the areas of sever
olganol [36]

Answer:

The domain and the range of the function are, respectively:

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Ran\{f\} = [0\,m^{2}, 10\,m^{2}]

Step-by-step explanation:

Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.

Dom\{f\} = [0\,m,5\,m]

Ran\{f\} = [0\,m^{2}, 10\,m^{2}]

8 0
3 years ago
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