All categories

2 years ago

Can someone plz help me with this

Mathematics

1 answer:

Grace [21]2 years ago

8 0

The answerssssssssssssss is 90.

You might be interested in

F(x) = x^2 + x - 11

Stella [2.4K]

Answer: y = − $\frac{39}{4}$

Step-by-step explanation:

8 0

2 years ago

Need help :) pleaseeeeeee :(

gayaneshka [121]

Answer: $x\geq 88$

This means that he has to save at least $88 or more to have enough money.

Step-by-step explanation:

He has $37 and he needs to save more (+) but we don't know how much more that is, so that's why that is our unknown value. (x). The sum of them has to be at least 125 or greater.

$37+x\geq 125$

Subtract 37

$x\geq125-37$

$x\geq 88$

8 0

2 years ago

What quadrant is 300π/276 in? Can u solve these too plz

Step2247 [10]

Answer:

Step-by-step explanation:

If the angle is greater than 360°, subtract 360° until the angle is less than 360°

3 0

1 year ago

if the probability of getting a 6 on a biased dice is 4/5, and you roll it 500 times, how many 6s would you expect to roll

Tresset [83]

I believe the answer would be 400 you take 4/5 and multiply it by 500

3 0

2 years ago

Find the expansion of cos x about the point x=0

ycow [4]

Answer:

Cos x = 1 - $\frac{x^2}{2!}$ + $\frac{x^4}{4!}$ - $\frac{x^6}{1!}$ + ...

Step-by-step explanation:

We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + $\frac{f''(a)(x-a)^2}{2!}$ + $\frac{f'''(a)(x-a)^3}{3!}$ + $\frac{f''''(a)(x-a)^4}{4!}$ + ...

Putting a = 0 and all the values from above in the expansion, we get,

Cos x = 1 - $\frac{x^2}{2!}$ + $\frac{x^4}{4!}$ - $\frac{x^6}{1!}$ + ...

8 0

2 years ago