Answer:
C
Step-by-step explanation:
The center of inscribed circle into triangle is point of intersection of all interior angles of triangle.
The center of circumscribed circle over triabgle is point of intersection of perpendicular bisectors to the sides.
Circumscribed circle always passes through the vertices of the triangle.
Inscribed circle is always tangent to the triangle's sides.
In your case angles' bisectors and perpendicular bisectors intesect at one point, so point A is the center of inscribed circle and the center of corcumsribed circle. Thus, these circles pass through the points X, Y, Z and G, E, F, respectively.
Convert the percent into a decimal 25% divided by 100 and do the same for both then add 9$ and all of the other decimals you get
Answer with Step-by-step explanation:
Zohar cut a rectangle with a length of 5x – 2
and a width of 3x + 1
We know that:
Perimeter of rectangle is:
Perimeter=2(length+width)
=2(5x-2+3x+1)
=2(8x-1)
=16x-2
Hence, expression which can be used to find the perimeter of the rectangle is:
16x-2
Now, when x=4
16x-2=16×4-2
=62
Hence, when x=4 ,Perimeter=62
Answer:
The answer is 11 Hope this helps ;)
Step-by-step explanation:
