Charges of +2 µC and +3 µC are 4 mm from each other. Raina’s group draws four diagrams trying to represent the electrical force
between the charges.
2 answers:
The correct diagram is shown below:
The charges of +2 µC and +3 µC are 4 mm from each other. The diagram below represents the electrical force between the charges. i.e. repulsive force. However the force of repulsion exerted by charge +3 µC on +2<span> µC will be more. The same charges repel each other and opposite charges attract each other.</span>
The charges of +2 µC and +3 µC are 4 mm from each other. The diagram below represents the electrical force between the charges. i.e. repulsive force. However the force of repulsion exerted by charge +3 µC on +2<span> µC will be more. The same charges repel each other and opposite charges attract each other.</span>
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Answer:
6.96 s
Explanation:
<u>Given:</u>
- u = initial speed of the automobile = 0 m/s
- a = constant acceleration of the automobile =
- v = constant speed of the truck = 8.7 m/s
<u>Assume:</u>
- t = time instant at which the automobile overtakes the truck.
At the moment the automobile and the truck both meat each other the distance travel by both vehicles must be the same.
Since t = 0 s is the initial condition. So, they both meet again at t = 6.96 s such that the automobile overtakes the truck.
Answer:
The farther star will appear 4 times fainter than the star that is near to the observer.
Explanation:
Since it is given that the luminosity of the 2 stars is same thus they radiate the same energy per unit time
Consider a spherical wave front of energy 'E' that leaves both the stars (Both radiate 'E' as they have same luminosity)
This Energy is spread over the whole surface area of sphere Thus when the wave front is at a distance 'r' the energy per unit surface area is given by
For the star that is twice away from the earth the distance is '2r' thus we will receive an energy given by
Hence we sense it as 4 times fainter than the nearer star.