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kirill [66]
3 years ago
14

#2 A car accelerates from rest at 4 m/s^2. What is the velocity of the car after 4 second?

Physics
1 answer:
solmaris [256]3 years ago
3 0
You use the equation Velocity = Acceleration X Time. 4x4=16m/s.


The car travels 18m in 3 seconds.
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Whats it called when a force can change the shape of an object?
alekssr [168]

Force applied causes deformation in the object. It changes the relative positions of constituent particles in the crystal lattice.
As soon as that happens, the interatomic or intermolecular forces come into play and they, tend to restore the solid back to it's original shape.

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However, no material is perfectly elastic and what happens is that, the body is not able to restore itself completely.

 
3 0
3 years ago
Read 2 more answers
2. A cinder block is sitting on a platform 20 m high. It weighs 16kg. The block has
Cerrena [4.2K]

Answer:

3136 Joules

Explanation:

Applying,

P.E = mgh.............. Equation 1

Where P.E = potential energy, m = mass of the cinder block, h = height of the platform, g = acceleration due to gravity.

From the question,

Given: m = 16 kg, h = 20 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

P.E = 16(20)(9.8)

P.E = 3136 Joules

Hence the potential energy of the cinder block is 3136 Joules

7 0
2 years ago
You guys cant answer a dam question I ask it fricking 6th grade questions
nexus9112 [7]

Answer:

calm down please its not that serious maybe no one saw it yet

Explanation:

7 0
3 years ago
An electric hoist does 500 joules of work lifting a crate 2 meters. How
LenKa [72]
Hope this answer helps
6 0
3 years ago
A point charge q1 is held stationary at the origin. A second charge q2 is placed at point a, and the electric potential energy o
likoan [24]

Answer:

U_{b}=+7.3*10^{-8}J

Explanation:

Given data

Electric potential at point a is Ua=5.4×10⁻⁸J

q₂ moves to point b where a negative work done on it  W_{a-b}=-1.9*10^{-8}J

Required

Electric potential energy Ub

Solution

When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:

W_{a-b}=U_{a}-U_{b}\\U_{b}=U_{a}-W_{a-b}

Now  substitute the given values

So

U_{b}=5.4*10^{-8}J-(-1.9*10^{-8}J)\\U_{b}=+7.3*10^{-8}J

3 0
3 years ago
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