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Vanyuwa [196]
3 years ago
12

How many teeth shows signs of decay?​

Physics
1 answer:
Zielflug [23.3K]3 years ago
6 0

Answer:

what do you mean

Explanation:

You might be interested in
Steam flows steadily through an adiabatic turbine. The inlet conditions of the steam are 4 MPa, 500◦C, and 80 m/s, and the exit
Cerrena [4.2K]

Answer:

a) ΔEC=-23.4kW

b)W=12106.2kW

c)A=0.01297m^2

Explanation:

A)

The kinetic energy is defined as:

\frac{m*vel^2}{2} (vel is the velocity, to differentiate with v, specific volume).

The kinetic energy change will be: Δ (\frac{mvel^2}{2})=\frac{m*vel_2^2}{2}-\frac{m*vel_1^2}{2}

Δ (\frac{mvel^2}{2})=\frac{m}{2}*(vel_2^2-vel_1^2)

Where 1 and 2 subscripts mean initial and final state respectively.

Δ(\frac{mvel^2}{2})=\frac{12\frac{kg}{s}}{2}*(50^2-80^2)\frac{m^2}{s^2}=-23400W=-23.4kW

This amount is negative because the steam is losing that energy.

B)

Consider the energy balance, with a neglective height difference: The energy that enters to the turbine (which is in the steam) is the same that goes out (which is in the steam and in the work done).

H_1+\frac{m*vel_1^2}{2}=H_2+\frac{m*vel_2^2}{2}+W\\W=m*(h_1-h_2)+\frac{m}{2} *(vel_1^2-vel_2^2)

We already know the last quantity: \frac{m}{2} *(vel_1^2-vel_2^2)=-Δ (\frac{mvel^2}{2})=23400W

For the steam enthalpies, review the steam tables (I attach the ones that I used); according to that, h_1=h(T=500C,P=4MPa)=3445.3\frac{kJ}{kg}

The exit state is a liquid-vapor mixture, so its enthalpy is:

h_2=h_f+xh_{fg}=289.23+0.92*2366.1=2483.4\frac{kJ}{kg}

Finally, the work can be obtained:

W=12\frac{kg}{s}*(3445.3-2438.4)\frac{kJ}{kg} +23.400kW)=12106.2kW

C) For the area, consider the equation of mass flow:

m=p*vel*A where p is the density, and A the area. The density is the inverse of the specific volume, so m=\frac{vel*A}{v}

The specific volume of the inlet steam can be read also from the steam tables, and its value is: 0.08643\frac{m^3}{kg}, so:

A=\frac{m*v}{vel}=\frac{12\frac{kg}{s}*0.08643\frac{m^3}{kg}}{80\frac{m}{s}}=0.01297m^2

Download pdf
7 0
4 years ago
What happens to the induced electric current if the number of loops is increased from one to three?
Stolb23 [73]

Answer:

C. It triples in magnitude (PLATO)

4 0
4 years ago
An object experiences an acceleration of 8.5 m/s^2 over a distance of 300 m. After that acceleration it has a velocity of 400 m/
Snezhnost [94]

Answer:

393.6m/s

Explanation:

Given parameters:

Acceleration  = 8.5m/s²

Distance  = 300m

Final velocity  = 400m/s

Unknown:

Initial velocity  = ?

Solution:

To solve this problem, we use the expression below;

             v² = u²  + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

      So;

               v²  - 2as = u²

        u²   = v²   - 2as

        u²  = 400²   - (2 x 8.5 x 300)  

         u   = 393.6m/s

7 0
3 years ago
Read 2 more answers
I know that the PE will be the same for all the objects, but other then that I'm confused on what is correct and what isn't. ​
joja [24]

Answer:

Neither aspects of Dominique are correct.

Explanation:

They will not have the same speed before hitting the ground.

The block C has an initial horizontal velocity v₀ₓ , therefore the total ultimate speed before hitting the ground is  v = √ v₀ₓ² + vy²

It didn't matter how the blocks were dropped, they all landed at the same time. If any block has an initial vertical velocity it will have a higher end velocity. If Dominique means dropped from the rest then the previous claim is true. It is important how they were dropped.

The Dominique must said : The vertical speed will be the same because of conservation of energy.

The fact is,  they all landed at the same time and that is true. And it is important how they are thrown away.

God is with you!!!

7 0
3 years ago
John is going to use a rope to pull his sister Laura across the ground in a sled through the snow. The rope makes an angle of 25
Liula [17]
The mass of Laura and the sled combined is 887.5 kg
5 0
3 years ago
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