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damaskus [11]
4 years ago
15

How much work is needed to push a 117- kg packing crate a distance of 2.75 m up an inclined plane that makes an angle of 28 o wi

th the horizontal, when inclined plane is frictionless

Physics
2 answers:
olga nikolaevna [1]4 years ago
7 0

Given Information:  

mass of crate = m = 117 kg

distance = d = 2.75 m  

Inclined plane angle = θ = 28°

Required Information:  

Work done = W = ?

Answer:  

Work done = 1480.3 N.m

Explanation:

Refer to the attached image, since there is no friction, the only force acting on the crate is the force in the downward direction given by

Fy = mgsin(θ)

Fy = 117*9.8*sin(28°)

Fy = 538.3 N

Now as we know work done is given by

W = Fy*d

W = 538.3*2.75

W = 538.3*2.75

W = 1480.3 N.m

Therefore, 1480.3 N.m of work is required to push a 117 kg  of crate to a distance of 2.75 m up an inclined plane making an angle of 28° with the horizontal surface.

Nataly_w [17]4 years ago
6 0

Answer:

W_{tot,min} = 1481.372\,J

Explanation:

The minimum total work is the work needed to counteract the work associated with the weight:

W_{tot, min} = W_{F}

W_{tot,min} = m\cdot g\cdot \sin \theta \cdot \Delta s

W_{tot,min} = (117\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (\sin 28^{\textdegree}) \cdot (2.75\,m)

W_{tot,min} = 1481.372\,J

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Answer:

A. Heat flows from an object at higher temperature to an object at lower temperature

Explanation:

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Heat doesn’t necessarily flow from an object with higher thermal energy to an object with lower thermal energy because an object has a higher thermal energy when it’s mass is more than the other. This makes B wrong.

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8 0
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a car with an initial velocity of 10ms north was accelerated for 6 second until it ha a final velocity of 25ms north, what is th
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Answer:

2 1/2 m/s^2 or 2.5m/s^2

Explanation:

From the question

final velocity v =25m/s

Initial velocity u =10m/s

time = 6 seconds

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Using the equation for linear motion

v = u + at

25 = 10 + a x 6

25 = 10 + a6

Subtract 10 from both sides

25-10 = 10 + a6 -10

25 - 10 = 10 -10 + a6

15 = a6

Divide both sides by 6

15/6 = a6/6

5/2 = a

a = 2 1/2 m/s^2 or 2.5m/s^2

8 0
3 years ago
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A car, initially traveling at 81.8 mi/h, slows to rest in 7.1 s. What is the car's acceleration?
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Answer:

a = -16.9 ft/s²

Explanation:

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if the initial direction is taken as the positive direction.

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You are to drive to an interview in another town, at a distance of 270 km on an expressway. the interview is at 11:15
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6 0
3 years ago
A potential difference exists between the inner and outer surfaces of the membrane of a cell. The inner surface is negative rela
kifflom [539]

Answer:

Explanation:

Given

Work required W=1.35\times 10^{-20}\ J

Work done to eject the sodium ion from interior of the cell is given by the product of charge and Potential difference between inner and outer surface of the cell.

W=q\times V

Charge on sodium ion q=1.6\times 10^{19}\ C

V=\frac{W}{q}

V=\frac{1.35\times 10^{-20}}{1.6\times 10^{19}}

V=0.0718\ V            

8 0
3 years ago
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