Torque of F1 = 30*0.025 = 0.75Nm anticlockwise
Torque of F2 = 34 * 0.020 = 0.68Nm clockwise
Horizontal component of F3:
cos 50 = x/20
x = 12.856 N
Torque of F3 horizontal component = 12.856 * 0.01 = 0.129Nm anticlockwise
0.129 + 0.75 - 0.68 = 0.199Nm anticlockwise
sorry I'm not sure is it correct
Answer:
T = 5163.89 N
Explanation:
Newton's first law:
∑F =0 Formula (1)
∑F : algebraic sum of the forces in Newton (N)
We define the x-axis in the direction parallel to the movement of the car on the ramp and the y-axis in the direction perpendicular to it.
Forces acting on the car
W: Weight of the car : In vertical direction
FN : Normal force : perpendicular to the ramp
T :Tension force: at angle of 31.0° above the surface of the ramp
Calculated of the Weight of the car (W)
W = m*g m: mass g:acceleration due to gravity
W = 1130-kg* 9.8 m/s² = 11074 N
x-y weight components
Wx = 11074 N*sin 25.0° = 4680.07 N
Wy = 11074 N*cos 25.0° = 10036.45 N
x-y Tension components
Tx = T*cos 25.0°
Ty = T*sin 25.0°
Newton's first law:
∑Fx =0 Formula (1)
Tx-Wx = 0
T*cos 25.0° - 4680.07 = 0
T*cos 25.0° = 4680.07
T = 4680.07 / cos 25.0°
T = 5163.89 N
The reaction of radiodecay of carbon C-14 is
C-14 --> N-14 + e- + (ve)
where e- is an electron and (ve) is an electron-type antineutrino.
Basically, when the carbon nucleus (atomic number: 6, mass number: 14) decays, a neutron of the nucleus converts into a proton (therefore, the mass number remains the same, 14, but the atomic number increases by 1, therefore it becomes nitrogen) and releases an electron-antineutrino pair.
So, the correct answer is C), N-14.
Given ,
initial velocity , u = 20 m/s
final velocity , v = 60 m/s
time taken = 2 seconds
Now ,
hope helpful~
They need more oxygen to function, so gas exchange needs to increase
