Ask question

Ask question

All categories

3 years ago

15

Electronic brainstorming, also called _____, is a technique used to help members of a group come together over a computer networ

k to generate ideas and alternatives for solving problems

1 answer:

yKpoI14uk [10]3 years ago

5 0

Answer:

Brainwriting

Explanation:

You might be interested in

aluminum has 13 electrons. how many electrons are found in the outermost energy level for this atom which energy level is the ou

Stolb23 [73]

<span>The outermost energy level of an element are called the valence shell, that holds the valence electrons. they consist of the highest energy level. In aluminum, the valence electrons are 3. </span>

8 0

3 years ago

Read 2 more answers

If you drop an object from rest, the distance it falls is given by (1/2)at2, where a is the acceleration of the object and t is

klio [65]

If,

$d \: = \: \frac{1}{2} a {t}^{2}$

then, with 3x time t, (suppose, new distance is h)

$h \: = \: \frac{1}{2} a {(3t)}^{2}$

$= \frac{1}{2} a9 {t}^{2}$

$= 9 \: \frac{1}{2} a{t}^{2}$

$= 9d$

Therefore, new distance h will be 9 times bigger than distance d.

answer: c

7 0

2 years ago

Please help me out !!!!!!

nikdorinn [45]

Answer:

89

Explanation:

8 0

3 years ago

What current flows through a 2.56-cm-diameter rod of pure silicon that is 20.0 cm long, when 1.00 ✕ 103 V is applied to it? (Suc

vfiekz [6]

Answer:

Current, I = 0.0011 A

Explanation:

It is given that,

Diameter of rod, d = 2.56 cm

Radius of rod, r = 1.28 cm = 0.0128 m

The resistivity of the pure silicon, $\rho=2300\ \Omega-m$

Length of rod, l = 20 cm = 0.2 m

Voltage, $V=1\times 10^3\ V$

The resistivity of the rod is given by :

$R=\rho\dfrac{L}{A}$

$R=2300\ \Omega-m\dfrac{0.2\ m}{\pi (0.0128\ m)^2}$

R = 893692.30 ohms

Current flowing in the rod is calculated using Ohm's law as :

V = I R

$I=\dfrac{V}{R}$

$I=\dfrac{10^3\ V}{893692.30\ \Omega}$

I = 0.0011 A

So, the current flowing in the rod is 0.0011 A. Hence, this is the required solution.

6 0

3 years ago

A loaded barge has a mass of 1 500 000 kg and is traveling at 3 m/s. If a tugboat applies an opposing force of 12 000 N for 10 s

yan [13]

Answer:

Explanation:

Initial momentum is 1.5e6(3) = 4.5e6 kg•m/s

An impulse results in a change of momentum

The tug applied impulse is 12000(10) = 120000 N•s or 0.12e6 kg•m/s

The remaining momentum is 4.5e6 - 0.12e6 = 4.38e6 kg•m/s

The barge velocity is now 4.38e6 / 1.5e6 = 2.92 m/s

The tug applies 0.012e6 N•s of impulse each second.

The initial barge momentum will be zero in

t = 4.5e6 / 0.012e6 = 375 s or 6 minutes and 15 seconds

To stop the barge in one minute(60 s), the tug would have to apply

4.5e6 / 60 = 75000 N•s /s or 75 000 N

5 0

2 years ago