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lozanna [386]
3 years ago
5

Burl the painter weighs 600 Newtons. He stands in the exact middle of his stage. There are two scale readings attached to the tw

o cords holding up the stage.
The image shows a painter standing in the middle of a scaffold that is hanging with two ropes on each end. Each rope has a spring scale.

What is the weight measured by each scale?

200 N
300 N
600 N
1200 N
Physics
1 answer:
chubhunter [2.5K]3 years ago
6 0

Answer:

T = 300 N

Explanation:

As we know that the painter is standing at the middle of the scaffold

So here the two ropes will exert same tension on the scaffold

So we will have

T_1 + T_2 = W

also we know

T_1 = T_2

so we will have

2T = W

T = \frac{W}{2}

so tension is half of the weight in both the strings

So it is

T = 300 N

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Series Circuit
A series circuit there is only one path for the electrons to flow (see image of series circuit). The main disadvantage of a series circuit is that if there is a break in the circuit the entire circuit is open and no current will flow. An example of a series would the the lights on many inexpensive Christmas trees. If one light goes out all of them will.



Parallel Circuit
In a parallel circuit the different parts of the electric circuit are on several different branches. There are several different paths that electrons can flow. If there is a break in one branch of the circuit electrons can still flow in other branches (see image of parallel circuit). Your home is wired in a parallel circuit so if one light bulb goes out the other will stay on.





HOPE THIS HELPS YOU MATE!!
I HAVE ALSO GIVEN THE EXPLANATION THINKING THAT IT MIGHT HELP YOU.
THANK YOU.
3 0
3 years ago
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The answer is A. Contrapositive
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3 years ago
(I) In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.6 cm. A second pro
Kipish [7]

Answer:

The second projectile was 1.41 times faster than the first.

Explanation:

In the ballistic pendulum experiment, the speed (v) of the projectile is given by:  

v = \frac{m + M}{m} \cdot \sqrt{2gh}

<em>where m: is the mass of the projectile, M: is the mass of the pendulum, g: is the gravitational constant and h: is the maximum height of the pendulum.   </em>

To know how many times faster was the second projectile than the first, we need to take the ratio for the velocities for the projectiles 2 and 1:    

\frac{v_{2}}{v_{1}} = \frac{\frac{m_{2} + M}{m_{2}} \cdot \sqrt{2gh_{2}}}{\frac{m_{1} + M}{m_{1}} \cdot \sqrt{2gh_{1}}}           (1)

<em>where m₁ and m₂ are the masses of the projectiles 1 and 2, respectively, and h₁ and h₂ are the maximum height reached by the pendulum by the projectiles 1 and 2, respectively.  </em>

Since the projectile 1 has the same mass that the projectile 2, we can simplify equation (1):

\frac{v_{2}}{v_{1}} = \frac{\sqrt{h_{2}}}{\sqrt{h_{1}}}  

\frac{v_{2}}{v_{1}} = \frac{\sqrt{5.2 cm}}{\sqrt{2.6 cm}}

\frac{v_{2}}{v_{1}} = 1.41  

Therefore, the second projectile was 1.41 times faster than the first.  

I hope it helps you!

8 0
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You have a battery marked " 6.00 V 6.00 V ." When you draw a current of 0.383 A 0.383 A from it, the potential difference betwee
Archy [21]

Answer:

V = 4.81 V

Explanation:

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  • We can calculate this loss, applying Ohm's law to the internal resistance, as follows:

        V_{rint} = I* r_{int}

  • The value of the potential difference between the terminals of the battery, is just the voltage of the battery, minus the loss in the internal resistance, as follows:

       V = V_{b} - V_{rint}  = 5.03 V = 6.0 V - 0.383 A* r_{int}

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         r_{int} = \frac{V_{b}-V}{I} =\frac{6.0V-5.03V}{0.383A} = 2.53 \Omega

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       V = V_{b} - V_{rint}  = 6.0 V - 0.469 A* 2.53 \Omega= 6.0 V - 1.19 V = 4.81 V

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