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lozanna [386]
3 years ago
5

Burl the painter weighs 600 Newtons. He stands in the exact middle of his stage. There are two scale readings attached to the tw

o cords holding up the stage.
The image shows a painter standing in the middle of a scaffold that is hanging with two ropes on each end. Each rope has a spring scale.

What is the weight measured by each scale?

200 N
300 N
600 N
1200 N
Physics
1 answer:
chubhunter [2.5K]3 years ago
6 0

Answer:

T = 300 N

Explanation:

As we know that the painter is standing at the middle of the scaffold

So here the two ropes will exert same tension on the scaffold

So we will have

T_1 + T_2 = W

also we know

T_1 = T_2

so we will have

2T = W

T = \frac{W}{2}

so tension is half of the weight in both the strings

So it is

T = 300 N

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Answer:

B = 7.9012*10^{-5}T

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To solve the problem, the concepts related to the magnetic field and the current produced in a lightning bolt are necessary.

The current is defined by the load due to time, that is to say

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So the current can be expressed as:

I = \frac{16}{1.5*10^{-3}}

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Once the current is found it is now possible to find the magnetic field, as this is given by the equation,

B =\frac{\mu_0}{2\pi}\frac{I}{r}

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A force of 660 n stretches a certain spring a distance of 0.300 m. what is the potential energy of the spring when a 70.0 kg mas
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A force of 660 n stretches a certain spring a distance of 0.300 m. what is the potential energy of the spring when a 70.0 kg mass hangs vertically from it?
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What is the definition of a volt in science?
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3 years ago
A 26 foot ladder is lowered down a vertical wall at a rate of 3 feet per minute. The base of the ladder is sliding away from the
lakkis [162]

Answer:

(i) 7.2 feet per minute.

(ii) No, the rate would be different.

(iii) The rate would be always positive.

(iv) the resultant change would be constant.

(v) 0 feet per min

Explanation:

Let the length of ladder is l, x be the height of the top of the ladder from the ground and y be the length of the bottom of the ladder from the wall,

By making the diagram of this situation,

Applying Pythagoras theorem,

l^2 = x^2 + y^2-----(1)

Differentiating with respect to t ( time ),

0=2x\frac{dx}{dt} + 2y\frac{dy}{dt}  ( l = 26 feet = constant )

\implies 2y\frac{dy}{dt} = -2x\frac{dx}{dt}

\implies \frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}

We have,

y = 10, \frac{dx}{dt}= -3\text{ feet per min}

\frac{dy}{dt}=\frac{3x}{10}-----(X)

(i) From equation (1),

26^2 = x^2 + 10^2

676=x^2 + 100

576 = x^2

\implies x = 24\text{ feet}

From equation (X),

\frac{dy}{dt}=\frac{3\times 24}{10}=7.2\text{ feet per min}

(ii) From equation (X),

\frac{dy}{dt}\propto x

Thus, for different value of x the value of \frac{dy}{dt} would be different.

(iii) Since, distance = Positive number,

So, the value of y will always a positive number.

Thus, from equation (X),

The rate would always be a positive.

(iv) The length of the ladder is constant, so, the resultant change would be constant.

i.e. x = increases ⇒ y = decreases

y = decreases ⇒ y = increases

(v) if ladder hit the ground x = 0,

So, from equation (X),

\frac{dy}{dt}=0\text{ feet per min}

3 0
3 years ago
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