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kakasveta [241]

2 years ago

5

Right Hand Rule 1 requires you to put the thumb of your right hand in the direction of current and your curled fingers will indi

cate the direction of magnetic field flow.
A. True

B. False

2 answers:

Oxana [17]2 years ago

7 0

Answer: no

Explanation:

Jet001 [13]2 years ago

3 0

Answer: false
explanation: magnetic field does that

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the resistance of a wire of length 80cm and of uniform area of cross-section 0.025cmsq., is found to be 1.50 ohm. Calculate spec

vivado [14]

$Specific\ resistance\ =resistivity\\
From\ formula\ on \ resistance:\ R= \frac{pL}{A}\ p-resistivity,\ L-length,\\ A-area\ of\ cross\ section\\
p= \frac{R*A}{L}= \frac{1,5Ohm*0,025*10^{-4}m^2 }{80* 10^{-2}m }=0,0003515625 Ohm*m$

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3 years ago

Someone help me with these two questions ASAP!!!

Sonbull [250]

For the first question it is the fourth option. Cryosphere is a term for the portions of earth that are covered in water when the water is in solid form. this includes both snow and ice.

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2 years ago

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Which of the following wire gage sizes is the thickest? <br> A. 8<br> B. 10<br> C. 14<br> D. 0

maks197457 [2]

A because it's the smaller the thicker you just can't have 0 gage

5 0

3 years ago

Which two formulas are used to calculate potential and kinetic energy

goblinko [34]

Answer:

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2 years ago

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Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.400mm wide. The diffraction pattern is observed

kogti [31]

Answer:

a) $y_{first}=5.3mm$

b) $y_{second}=10.6-5.3 =5.3 mm$

Explanation:

a)

The width of the central bright in this diffraction pattern is given by:

$y=\frac{m\lambda D}{a}$ when m is a natural number.

here:

m is 1 (to find the central bright fringe)
D is the distance from the slit to the screen
a is the slit wide
λ is the wavelength

So we have:

$y_{first}=\frac{633*10^{9}*3.35}{0.0004}$

$y_{first}=5.3mm$

b)

Now, if we do m=2 we can find the distance to the second minima.

$y_{2}=\frac{2*633*10^{9}*3.35}{0.0004}$

$y_{2}=10.6 mm$

Now we need to subtract these distance, to get the width of the first bright fringe :

$y_{second}=10.6-5.3 =5.3 mm$

I hope it heps you!

4 0

2 years ago