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arlik [135]
4 years ago
13

Which source would provide the most reliable information about the safety of nuclear power plants?

Physics
1 answer:
soldier1979 [14.2K]4 years ago
8 0

This paper is about the main conventional types of nuclear reactor. For more advanced types, see Advanced Reactors and Small Reactors papers, and also Generation IV reactors.

A nuclear reactor produces and controls the release of energy from splitting the atoms of certain elements. In a nuclear power reactor, the energy released is used as heat to make steam to generate electricity. (In a research reactor the main purpose is to utilise the actual neutrons produced in the core. In most naval reactors, steam drives a turbine directly for propulsion.)

The principles for using nuclear power to produce electricity are the same for most types of reactor. The energy released from continuous fission of the atoms of the fuel is harnessed as heat in either a gas or water, and is used to produce steam. The steam is used to drive the turbines which produce electricity (as in most fossil fuel plants).

The world's first nuclear reactors operated naturally in a uranium deposit about two billion years ago. These were in rich uranium orebodies and moderated by percolating rainwater. The 17 known at Oklo in west Africa, each less than 100 kW thermal, together consumed about six tonnes of that uranium. It is assumed that these were not unique worldwide.

Today, reactors derived from designs originally developed for propelling submarines and large naval ships generate about 85% of the world's nuclear electricity. The main design is the pressurised water reactor (PWR) which has water at over 300°C under pressure in its primary cooling/heat transfer circuit, and generates steam in a secondary circuit. The less numerous boiling water reactor (BWR) makes steam in the primary circuit above the reactor core, at similar temperatures and pressure. Both types use water as both coolant and moderator, to slow neutrons. Since water normally boils at 100°C, they have robust steel pressure vessels or tubes to enable the higher operating temperature. (Another type uses heavy water, with deuterium atoms, as moderator. Hence the term ‘light water’ is used to differentiate.)

Components of a nuclear reactor

There are several components common to most types of reactors:

Fuel. Uranium is the basic fuel. Usually pellets of uranium oxide (UO2) are arranged in tubes to form fuel rods. The rods are arranged into fuel assemblies in the reactor core.*
* In a new reactor with new fuel a neutron source is needed to get the reaction going. Usually this is beryllium mixed with polonium, radium or other alpha-emitter. Alpha particles from the decay cause a release of neutrons from the beryllium as it turns to carbon-12. Restarting a reactor with some used fuel may not require this, as there may be enough neutrons to achieve critical when control rods are removed.

Moderator. Material in the core which slows down the neutrons released from fission so that they cause more fission. It is usually water, but may be heavy water or graphite.

Control rods. These are made with neutron-absorbing material such as cadmium, hafnium or boron, and are inserted or withdrawn from the core to control the rate of reaction, or to halt it.*  In some PWR reactors, special control rods are used to enable the core to sustain a low level of power efficiently. (Secondary control systems involve other neutron absorbers, usually boron in the coolant – its concentration can be adjusted over time as the fuel burns up.)
* In fission, most of the neutrons are released promptly, but some are delayed. These are crucial in enabling a chain reacting system (or reactor) to be controllable and to be able to be held precisely critical.

Coolant. A fluid circulating through the core so as to transfer the heat from it.  In light water reactors the water moderator functions also as primary coolant. Except in BWRs, there is secondary coolant circuit where the water becomes steam. (See also later section on primary coolant characteristics)





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if the mass of the marble is 0.025kg, and you assume that on the first drop of your roller coaster (height=8cm) the marble is fa
Nookie1986 [14]

1. What is the force of the marble?

For an object near the surface of the earth, the gravitational force acting upon the object is given by:

F = mg

F is the gravitational force, m is the object's mass, and g is the acceleration of objects due to earth's gravity.

Given values:

m = 0.025kg, g = 9.8m/s²

Plug in the given values and solve for F:

F = 0.025×9.8

F = 0.25N

2. What is the marble's potential energy at the start of its fall?

The gravitational potential energy of an object near the earth's surface is given by:

PE = mgh

PE is the potential energy, m is the object's mass, g is the acceleration of objects due to earth's gravity, and h is the object's relative height.

new given values:

h = 0.08m

Since F = mg, you can simply multiply F×h to get PE. Use the result from question 1:

PE = F×h

PE = 0.25×0.08

PE = 0.02J

4 0
3 years ago
You illuminate a slit with a width of 70.3 μm with a light of wavelength 719 nm and observe the resulting diffraction pattern on
Zielflug [23.3K]

Answer:

4.3 cm

Explanation:

We are given that

Width,d=70.3\mu m=70.3\times10^{-6} m

1\mu m=10^{-6} m

Wavelength,\lambda=719 nm=719\times 10^{-9} m

1nm=10^{-9} m

r=2.11 m

We have to find the width in cm of the pattern.

The angle for the first minimum m=1

sin\theta_{min}\approx \theta=\frac{\lambda}{d}=\frac{719\times 10^{-9}}{70.3\times 10^{-6}}=0.0102 rad

y=r\theta=2.11\times 0.0102=0.0215 m

The width of the pattern=2y=2\times 0.0215=0.043 m=0.043\times 100=4.3 cm

8 0
3 years ago
A bicyclist moves along a straight line with an initial velocity vo and slows downs. Which of the following the best describes t
xeze [42]

????????????????????

3 0
3 years ago
A wave is passing through a uniform medium. As the frequency of this wave increases, its wavelength
Lerok [7]

B. Decreases

Why: Because the longer the wavelength the lower the frquency. The shorter the wavelength the higher the frequency.

5 0
4 years ago
Read 2 more answers
What is the
Len [333]

Answer:

d=5\ g/cm^3

Explanation:

Given that,

Mass of the object, m = 100 grams

Volume of the object, V = 20 cm³

We need to find the density of the object. We know that, density is equal to mass per unit volume. So,

d=\dfrac{m}{V}\\\\d=\dfrac{100\ g}{20\ cm^3}\\\\d=5\ g/cm^3

So, the density of the object is equal to 5\ g/cm^3.

6 0
3 years ago
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