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2 years ago

Which is true about sugar dissolving in water?

1 answer:

7 0

Sugar is the solute since it is the thing that is being dissolved.
And the water is the solvent since it is the thing that contains the solute.

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How many electrons would Potassium with a +2 charge have?

Dennis_Churaev [7]

Answer:

17 electrons

Potassium normally has 19 electrons but the +2 implies that Potassium lost 2 electrons making the total be 17 electrons

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2 years ago

Sodium (Na) A Homogeneous Mixture B Element C Compound D Heterogeneous Mixture

laiz [17]

Sodium is categorized as a B. Element.

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2 years ago

Which of the following wouldn't be a good tool to use when measuring pH values of solutions?

aev [14]

litmus paper

Because it will just tell if the solution is acidic or basic, it won't tell the pH

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2 years ago

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2. What was the primary goal of the Apollo program?

babunello [35]

Answer:

Explanation:

to conduct scientific exploration of the moon

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2 years ago

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It has been suggested that the surface melting of ice plays a role in enabling speed skaters to achieve peak performance. Carry

vesna_86 [32]

Explanation:

Relation between pressure, latent heat of fusion, and change in volume is as follows.

$\frac{dP}{dT} = \frac{L}{T \times \Delta V}$

Also, $\frac{L}{T} = \Delta S^{fusion}_{m}$

where, $\Delta V^{fusion}_{m}$ is the difference in specific volumes.

Hence, $\frac{dP}{dT} = \frac{\Delta S^{fusion}_{m}}{\Delta V^{fusion}_{m}}$

As, $\Delta S^{fusion}_{m} = \frac{L}{T} = \frac{6010}{273.15}$ = 22.0 J/mol K

And, $\Delta V^{fusion}_{m} = \frac{M}{d_{H_{2}O}} - \frac{M}{d_{ice}}$ ...... (1)

where, $d_{H_{2}O}$ = density of water

$d_{ice}$ = density of ice

M = molar mass of water = $18.02 \times 10^{-3} kg$

Therefore, using formula in equation (1) we will calculate the volume of fusion as follows.

$\Delta V^{fusion}_{m} = \frac{M}{d_{H_{2}O}} - \frac{M}{d_{ice}}$

= $\frac{18.02 \times 10^{-3}}{997} - \frac{18.02 \times 10^{-3}}{920}$

= $-1.51 \times 10^{-6}$

Therefore, calculate the required pressure as follows.

$\frac{dP}{dT} = \frac{22}{-1.51 \times 10^{-6}}$

= $1.45 \times 10^{7} Pa/K$

or, = 145 bar/K

Hence, for change of 1 degree pressure the decrease is 145 bar and for 4.7 degree change dP = $145 \times 4.7 bar$

= 681.5 bar

Thus, we can conclude that pressure should be increased by 681.5 bar to cause 4.7 degree change in melting point.

5 0

2 years ago