Answer:
The answer is A. a wave of vibrating electric and magnetic energy.
Answer:
Explanation:
Not Many
1 mol of CO has a mass of
C = 12
O = 16
1 mol = 28 grams.
1 mol of molecules = 6.02 * 10^23
x mol of molecules = 3.14 * 10^15 Cross multiply
6.02*10^23 x = 1 * 3.14 * 10^15 Divide by 6.02*10^23
x = 3.14*10^15 / 6.02*10^23
x = 0.000000005 mols
x = 5*10^-9
1 mol of CO has a mass of 28
5*10^-9 mol of CO has a mass of x Cross Multiply
x = 5 * 10^-9 * 28
x = 1.46 * 10^-7 grams
Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample
Answer: Theoretical yield of
produced by 8.96 g of S is 33.6 g
Explanation:
To calculate the moles :
![\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20solute%7D%3D%5Cfrac%7B%5Ctext%7Bgiven%20mass%7D%7D%7B%5Ctext%7BMolar%20Mass%7D%7D)
![\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%7D%20S%3D%5Cfrac%7B8.96g%7D%7B32g%2Fmol%7D%3D0.28moles)
The balanced chemical equation is:
According to stoichiometry :
2 moles of
produce = 3 moles of ![SO_3](https://tex.z-dn.net/?f=SO_3)
Thus 0.28 moles of
will produce=
of
Mass of ![SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g](https://tex.z-dn.net/?f=SO_3%3Dmoles%5Ctimes%20%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D0.42moles%5Ctimes%2080g%2Fmol%3D33.6g)
Thus theoretical yield of
produced by 8.96 g of S is 33.6 g