If I'm reading your question correctly: "<span>F(x)=7x+9/8x-9 when -f(x)," then all you have to do to find -f(x) would be to put a negative sign in front of ALL
of 7x + 9 / (8x-9):
9
- f(x) = -7x - --------
8x-9</span>
Answer:
A) -2
Step-by-step explanation:
The form is indeterminate at x=0, so L'Hopital's rule applies. The resulting form is also indeterminate at x=0, so a second application is required.
Let f(x) = x·sin(x); g(x) = cos(x) -1
Then f'(x) = sin(x) +x·cos(x), and g'(x) = -sin(x).
We still have f'(0)/g'(0) = 0/0 . . . . . indeterminate.
__
Differentiating numerator and denominator a second time gives ...
f''(x) = 2cos(x) -sin(x)
g''(x) = -cos(x)
Then f''(0)/g''(0) = 2/-1 = -2
_____
I like to start by graphing the expression to see if that is informative as to what the limit should be. The graph suggests the limit is -2, as we found.
Answer: 97.50
Step-by-step explanation: APEX
so basically for this problem you're just going to plug in the point (3,-3) into every equation, keeping in mind that the 3 is the x value and that the -3 is the y value. once you plug it in you can just use order of operations (pemdas) to solve.
the equations that do work with the point (3,-3) are (2x+4y=-6)
(2x-3y=15)
(8x+3y=15)
(7x-2y=-24)
Step-by-step explanation:
so to work one of these problems you take (2x+4y=-6) and plug in your variables.
2(3)+4(-3)=-6
then you're going to multiply
6-12=-6
the subtract the negative twelve from the 6
-6=-6
so we get a true statement. if you do this and the two numbers don't match then the equation does not work with your point. I hope this helps!
Answer:
51
1−2+3−4+5−.....+101
=(1+3+5+.....+101)−(2+4+6+.....+100)
=(1+3+5+.....+101)−2(1+2+3+.....+50)
=(51)
2
−2(
2
50(50+1)
)
=2601−2×1275
=2601−2550
=51