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marysya [2.9K]
3 years ago
10

What is the absolute deviation for the data point at 1 if the mean is 5? 1 2 4 5

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
7 0
If the mean = 5.

Absolute deviation = |x - μ|, where μ =  mean.

For data point x =1, 

For x = 1, the absolute deviation = |1 - 5| =|-4| = 4
atroni [7]3 years ago
7 0

Answer:

4

Step-by-step explanation:

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Find the length and area of rectangle whose diagonal is =26cm and breath is =10cm​
givi [52]

Answer:

240cm²

explanation

Diagonal ²=Length ²+breath ²

26²=10²+length ²

676=100+length ²

576=length ²

length=24cm

Area of a rectangle=length×breath

Area=24×10

=240cm²

3 0
3 years ago
A polygon has the following coordinates: A(3,1), B(5,3), C(2,5), D(-1,5), E(-4,3), F(-2,1). Find the length of DC.
nlexa [21]

To find the length of a line given two points, we are going to use the distance formula, which is defined below:

D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

((x_1, y_1) and (x_2, y_2) are the two points)


The points in this problem are (2, 5) and (-1, 5). We can find the distance of DC by substituting these values into the distance formula and simplifying, as shown below:

D = \sqrt{(-1 - 2)^2 + (5 - 5)^2

  • Substitute values into formula

D = \sqrt{(-3)^2}

  • Combine like terms and then simplify 0^2 to 0

D = \sqrt{9}

  • Compute (-3)^2 = 9

D = 3

  • Compute \sqrt{9} = 3

The length of DC is 3.

7 0
3 years ago
(5k-5)(4k-5) foil and distributive
fenix001 [56]
<span>(a+b)(c+d)=ab+ad+bc+bd
(5k-4)(4k-5)=20k^2+-25k-16k+20=20k^2-41k+20

Hope this helps!</span>
6 0
3 years ago
One hundred nautical miles equals about 185 kilometers. To the nearest kilometer, how far in kilometers is 195 nautical miles?
artcher [175]
(d km)/(195 nm) = (185 km)/(100 nm)
d = 1.95*185 km ≈ 361 km

195 nautical miles is about 361 kilometers.
5 0
3 years ago
Read 2 more answers
Please help I will mark brainly!!!!
kondaur [170]
2,5,8,11,14 because it’s going by 3’s.
5 0
3 years ago
Read 2 more answers
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