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2 years ago

What is the absolute deviation for the data point at 1 if the mean is 5? 1 2 4 5

2 answers:

7 0

If the mean = 5.

Absolute deviation = |x - μ|, where μ = mean.

For data point x =1,

For x = 1, the absolute deviation = |1 - 5| =|-4| = 4

atroni [7]2 years ago

7 0

Answer:

Step-by-step explanation:

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See Below.

Step-by-step explanation:

Statements: Reasons:

$1)\, XY=XZ$ Given

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$\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}$ Angle Addition

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$5) \text{ $m\angle XYQ=m\angle QYZ$}$ Definition of Bisector

$\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}$ Substitution

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$8)\text{ $ZP$ bisects $\angle XZY$}$ Given

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$12)\text{ }m\angle QYZ=m\angle PZY$ Division Property of Equality

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*For clarification:

∠Y = ∠Z

YZ = YZ (or ZY)

∠PZY = ∠QYZ

So, Angle-Side-Angle Congruence:

ΔYZP is congruent to ΔZYQ

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