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yanalaym [24]
3 years ago
10

A reaction produces 0.875 moles of h2o. how many molecules are produced?

Chemistry
1 answer:
alekssr [168]3 years ago
3 0
<span>Avogadro's constant/number is 6.022 Ă— 10^23 molecules for every 1 mole of substance. And reaction produces 0.875 moles of h2o. So, Number of molecules produced = Avagardo's number x Number of moles of h2o produced. Number of molecules produced = (6.022 Ă— 10^23) x (0.875) Number of molecules produced =5.26925 Ă—10^23 molecules.</span>
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Explanation:

First, we will calculate fuel consumption is as follows.

         372 L/min \times 1000 ml/L \times 0.730 g/ml \times \frac{1}{60} min/s

           = 4526 g/s

Now, we will calculate the power as follows.

        Power = Fuel consumption rate × -enthalpy of combustion

                    = 4526 g/s \times -26.5 kJ/g

                    = 1.19 \times 10^{5} kW

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3 years ago
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Answer:

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Explanation:

8 0
3 years ago
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11111nata11111 [884]

Formula mass, molar mass and Avagadro's number.

Explanation:

number of atoms in a compound can be calculated by knowing the molar mass of the compound or element, the result will be multiplied by avagadro's number (6.022*10^23)

1 mole of a substance is equal to Avagadro number of atoms.

If the number of moles is known of a compound or element its molar mass can be calculated as:

n= Weight of the compound/element given/ molecular weight of the same.

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5 0
4 years ago
The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m
monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x 10^{-12} m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x 10^{-12}

                                               = 260 x 10^{-12} m

Given a distance of 1.30 mm = 1.30 x 10^{-3} m,

The number of vanadium atoms required to span the distance = \frac{1.3*10^{-3} }{260*10^{-12} }

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

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3 years ago
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