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grin007 [14]
3 years ago
14

PLEASE ANSWER ASAP

Chemistry
2 answers:
RSB [31]3 years ago
5 0

Question:

What would be the best way to increase the rate

of the reaction?

Answer:

D. She could make the original solutions at higher concentrations.

Llana [10]3 years ago
3 0

Answer:

D. She could make the original solutions at higher concentrations.

Explanation:

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Harry stores toxic chemical waste in a large steel tank that has only 15% of its volume underground. Jena lives in the wildernes
Anvisha [2.4K]

Answer:

Only Harry and Jena

Explanation:

Under federal regulations, an UST is any one or a combination of tanks such that the volume of an accumulation of regulated substances is 10% or more beneath the surface of the ground.

Any UST system holding a mixture of hazardous waste and other regulated substances are also are not covered by federal regulations regarding USTs.

Farm or residential tank of capacity more than 11 gallons used for storing motor fuel is covered by federal regulations regarding USTs.

According to the given question,

Only Harry and Jena are covered by federal regulations regarding USTs.

7 0
3 years ago
How many grams of aluminum are necessary to produce 11 L of hydrogen gas at STP?? <br> PLEASE HELP
-BARSIC- [3]
9.0 grams will produce 11 L of hydrogen
6 0
2 years ago
Read 2 more answers
How does vapor pressure affect intermolecular forces.
Grace [21]

Answer:

it is directly related to the intermolecular forces present between its molecules

3 0
2 years ago
PLEASE
Nimfa-mama [501]
A. 1,5,3,4

the 3 and 4 increase the number of oxygens on the right side to 10 so you have to put a 5 in front of the oxygen of the left side to balance it out
5 0
3 years ago
Suppose that 0.50 grams of barium-131 are administered orally to a patient. Approximately how many milligrams of the barium woul
nalin [4]

Two months later 13.8 milligrams of the barium-131 still be radioactive.

<h3>How is the decay rate of a radioactive substance expressed ? </h3>

It is expressed as:

A = A_{0} \times (\frac{1}{2})^{t/T}

where,

A = Amount remaining

A₀ = Initial Amount

t = time

T = Half life

Here

A₀ = 0.50g

t  = 2 months = 60 days

T = 11.6 days  

Now put the values in above expression we get

A = A_{0} \times (\frac{1}{2})^{t/T}

   = 0.50 \times (\frac{1}{2})^{60/11.6}

   = 0.50 \times (\frac{1}{2})^{5.17}

   = 0.50 × 0.0277

   = 0.0138 g

   = 13.8 mg          [1 mg = 1000 g]

Thus from the above conclusion we can say that Two months later 13.8 milligrams of the barium-131 still be radioactive.

Learn more about the Radioactive here: brainly.com/question/2320811

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Suppose that 0.50 grams of ban that 0.50 grams of barium-131 are administered orally to a patient. Approximately many milligrams of the barium would still be radioactive two months later? The half-life of barium-131 is 11.6 days.

3 0
1 year ago
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