Answer:
So, you're dealing with a sample of cobalt-60. You know that cobalt-60 has a nuclear half-life of
5.30
years, and are interested in finding how many grams of the sample would remain after
1.00
year and
10.0
years, respectively.
A radioactive isotope's half-life tells you how much time is needed for an initial sample to be halved.
If you start with an initial sample
A
0
, then you can say that you will be left with
A
0
2
→
after one half-life passes;
A
0
2
⋅
1
2
=
A
0
4
→
after two half-lives pass;
A
0
4
⋅
1
2
=
A
0
8
→
after three half-lives pass;
A
0
8
⋅
1
2
=
A
0
16
→
after four half-lives pass;
⋮
Explanation:
now i know the answer
a b c d no a no b yes c no d ok
Phosphorus 31. because the mass of sulfur 32 minus the number of protons 16 = 16 neutrons and the mass of phosphorus 31 minus the number of protons 15 = 16 neutrons
Final answer: phosphorus 31
Answer:
See explanation
Explanation:
the Cis structure, we can have two possibilities. The methyl groups can go both in <u>axial positions</u> or both in <u>equatorial positions</u>. We have to remember that cis it means <u>"same orientation"</u>, so in the axial positions, both methyl groups go up. (Both have the same orientation). In the equatorial positions, both groups go down.
In the axial positions, we will have <u>more steric hindrance</u> because the groups are close to each other. Therefore, we will have <u>more energy</u> and the structure will be <u>less stable</u>. In the equatorial positions, we <u>dont have any steric hindrances</u>, so we will have <u>less energy and more stability</u>.
See figure 1
I hope it helps!