Answer:
d = 1.954 Km
Explanation:
given,
total distance, D = 2.5 Km
in stretch A to B =
speed = 99 Km/h = 99 x 0.278 = 27.22 m/s time =t
in stretch B to C
time = 3.4 s
In stretch C to D
speed = 48 Km/h = 48 x 0.278 = 13.34 m/s time =t
we know,
distance = speed x time
distance of BC
using equation of motion
v = u + a t
27.22 = 13.34 - a x 3.4
a = 4.08 m/s²
uniform deceleration is equal to 4.08 m/s²
distance traveled in BC
s = 68.94 m
3000 = 27.5 t + 68.94 + 13.33 t
40.83 t = 2931.06
t = 71.79 s
distance travel in AB
distance = s x t
d = 27.22 x 71.79
d = 1954 m
d = 1.954 Km
distance between A and B is equal to 1.954 Km.
A charge-coupled device (CCD) is a light-sensitive integrated circuit that captures images by converting photons to electrons.
A touch screen is a computer display screen that is also an input device. The screens are sensitive to pressure; a user interacts with the computer by touching pictures or words on the screen.
The similarity is the sensitivity.
The difference is CCD scans or ‘takes images’, whereas touch-screen is where a user interacts with the software.
Hope this helps!
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The law of conservation states that the total amount of energy of an isolated system remains constant; it is said to be conserved over time
I think it's C plate movement at fault lines
I'm not sure but it's probably C because you are treating a health problem.
