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3 years ago

Answer a and b please......

Mathematics

1 answer:

Ray Of Light [21]3 years ago

4 0

A complex fraction is fraction divided by another fraction. It's complex.. :-3

(a) (2 1/4 lettuce) / (1/2 tomato)
(b) the amount of tomatos is doubled (1/2 lb --> 1 lb) So double the amount of lettuce. (2 1/4 * 2 = 4 1/2 cup lettuce)

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HELP?????????????????????/

Gemiola [76]

Answer:

you have to make x-3 and x-7 equal to zero...

x = 3 or x=7

"A"

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Help me ..... im stuck here

Jobisdone [24]

The answer is (3p-5pt)/12

remove parenthesis but the terms are connected.

4 0

3 years ago

Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,

Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

$\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$

In order to use t*, we need to check conditions for using a t-distribution first.

Random for both samples -- NOT STATED in the problem ∴ proceed with caution!
Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
Normality: CLT is not met; n < 30 for both locations A and B ∴ proceed with caution!

Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.

Solve for t*:

We need the tail area first.

$\displaystyle \frac{1-.9}{2}= .05$

Next we need the degree of freedom.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

df for A: 13 - 1 = 12
df for B: 18 - 1 = 17
df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding t-score for df = 5 and tail area = .05.

t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

$\overline {x}_A=39$
$s_A=8$
$n_A=13$
$\overline {x}_B = 55$
$s_B=2$
$n_B=18$
$t^{*}=-2.015$

Substitute the variables into the formula: $\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$ .

$39-55 \ \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}$

Simplify this expression.

$-16 \ \pm \ -2.015 (\sqrt{5.1453} \ )$
$-16 \ \pm \ 3.73139$

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

$(-20.5707,-11.4293)$

If we want to interpret the confidence interval of (-20.5707, -11.4293), we can say...

We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.

5 0

2 years ago

A flagpole casts a shadow 16.60 meters long Tim stands at a distance of 12.45 meters from the base of the flagpole such that the

coldgirl [10]

This problem is solely on right triangles, wherein the Pythagorean theorem may be applied. We must first find the angle of elevation of the flagpole using Tim's height and the difference between the shadow of the flagpole and Tim's distance from the flagpole. Therefore tan a = 1.65/(16.6-12.5) where a=21.68 degrees. We use this angle to determine the height of the flagpole. tan 21.68 = x/ 16.6 where x=height of flagpole=6.6 meters.

6 0

3 years ago

Evaluate.

lozanna [386]

Answer: 289/900

Explanation: I did this before

4 0

1 year ago

Read 2 more answers