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Anettt [7]
3 years ago
13

Quick answers please!​

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0

Answer:

27.44

Step-by-step explanation:

area of the half sircle = 12.56

area of the rectangle = 40

area of the shaded protion = 40 -12.56

=27.44 square yards

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32.567+135.0+1.4567=<br><br> what is the answer
Mrrafil [7]
=169.0237
<span><span>32.567+135</span>+1.4567
</span><span>=<span>167.567+1.4567
</span></span><span>=<span>169.0237
♥Hope this helps!♥</span></span>
7 0
3 years ago
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The surface area of a cylinder is 500 square feet; the lateral surface area is 320 square feet. Give the area of a base.
ohaa [14]

Answer: try your best

Step-by-step explanation:

7 0
3 years ago
Heather is going to graph y = -3x2 + 3. How is the parent graph transformed?
Yuki888 [10]
Any x² graph is a parabola. The negative in front is going to flip the parabola upside down to look like a camel hump. The 3 is going to make the graph narrower. The three at the end makes the y intercept 3. So the top of the graph will be shifted up to (0,3).
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3 0
3 years ago
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The equation C = 5 9 F − 160 9 gives the relation between temperature readings in Celsius and Fahrenheit.
Pavel [41]

Step-by-step explanation:

The question is wrong. The correct equation is :

C=\frac{5}{9}F-\frac{160}{9}

We know that the equation gives the relation  between temperature readings in Celsius and Fahrenheit.

Therefore, giving that we know the value in Fahrenheit ''F'' we can find the reading in Celsius ''C''. This define a function C(F) that depends of the variable ''F''.

So for the incise (a) we answer Yes, C is a function of F.

For (b) we need to find the mathematical domain of this function. Giving that we haven't got any mathematical restriction, the mathematical domain of the function are all real numbers.

Dom (C) = ( - ∞ , + ∞)

For (c) we know that the water in liquid state and at normal atmospheric pressure exists between 0 and 100 Celsius.

Therefore the range will be

Rang (C) = (0,100)

Now, we need to find the domain for this range. We do this by equaliting and finding the value for the variable ''F'' :

For C = 0 :

0=\frac{5}{9}F-\frac{160}{9} ⇒ F=32

And for C = 100 :

100=\frac{5}{9}F-\frac{160}{9} ⇒ F=212

Therefore, the domain as relating temperatures of water in its liquid state is

Dom (C) = (32,212)

For (d) we only need to replace in the equation by F=71 and find the value of C ⇒

C=\frac{5}{9}F-\frac{160}{9} ⇒

C=(\frac{5}{9})(71)-\frac{160}{9}

C=\frac{65}{3} ≅ 21.67

C(71) = 21.67 °C

4 0
2 years ago
What is 7539 increased by 3200
ddd [48]
Increased just means +
10739 is the sum
3 0
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