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rosijanka [135]
4 years ago
11

The electromagnetic waves that have the lowest frequencies are called a. radio waves. c. ultraviolet waves. b. microwaves. d. x-

rays. Please select the best answer from the choices provided A B C D
Physics
1 answer:
IgorC [24]4 years ago
3 0

the answer to that would be radio waves which would be answer A

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12. A 20-newton cart is lifted up 0.40 meters to the top of a ramp.
Hitman42 [59]

Answer:

8 joules

Explanation:

Just did it

8 0
3 years ago
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Which of the following statements are true with regard to resistivity?
siniylev [52]

Resistivity is material property. It depends only on temperature. For the same material with different length and area, resistivity remains the same until temperature remains constant.

<h3>HOPE IT HELPS YOU......</h3>

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4 0
3 years ago
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During a practice shot put throw, the 7.9-kg shot left world champion C. J. Hunter's hand at speed 16 m/s. While making the thro
koban [17]

Answer:

a)   a = 91.4 m / s²,  b)    t = 0.175 s, c)  

Explanation:

a) This is a kinematics exercise

           v² = vox ² + 2a (x-xo)

           a = v² - 0/2 (x-0)

           

let's calculate

          a = 16² / 2 1.4

          a = 91.4 m / s²

b) the shooting time

          v = vox + a t

          t = v-vox / a

          t = 16 / 91.4

          t = 0.175 s

c) let's use Newton's second law

          F = ma

          F = 7.9 91.4

          F = 733 N

4 0
3 years ago
A 0.145 kg baseball is thrown with a velocity of 40 m/s. What is the baseball's momentum?
Rom4ik [11]
The momentum, p, is the product of the mass and the velocity:
p = m*v = 0.145 kg * 40 m/s = 5.8 kg*m/s
3 0
3 years ago
Calculate the energy (in MeV) released when α decay converts uranium 232U (atomic mass = 232.037146 u) into thorium 228Th (atomi
Studentka2010 [4]

To solve this problem it is necessary to apply the concepts related to the energy released through the mass defect.

Mass defect can be understood as the difference between the mass of an isotope and its mass number, representing binding energy.

According to the information given we have that the reaction presented is as follows:

^{232}U_{92} \Rightarrow ^{228}Th_{90}+^4He_2

The values of the atomic masses would then be:

Th = 232.037146 u

Ra = 228.028731 u

He = 4.0026

The mass difference of the reaction would then be represented as

\Delta m = 232.037146 u - (228.028731 u + 4.002603 u )

\Delta m = 0.005812 u

From the international measurement system we know that 1 atomic mass unit is equivalent to 931.5 MeV,

\Delta m = 0.005812 u (\frac{931.5MeV}{1u})

\Delta m = 5.414MeV

Therefore the energy is 5.414MeV

3 0
3 years ago
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