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mote1985 [20]
3 years ago
8

What percentage of the acceleration at Earth's surface is the acceleration due to gravity at the position of a satellite located

489 km above Earth
Physics
1 answer:
lana66690 [7]3 years ago
7 0

Answer:

Explanation:

The formula for variation in the value of g due to height h is given by the following relation .

g₁ = g₀ ( 1 - h / R )

g₁ and  g₀ are value of acceleration due to gravity at height h from surface and at surface and  R is radius of the earth .

R = 6370 km , h = 489 km ( given )

g₁ = g₀ ( 1 - 489 / 6370 )

= .923 g₀

g₁ in percent terms = .923 x 100

= 92.3 % .

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a 4kg block is attatched to a vertical sspring constant 800n/m. the spring stretches 5cm down. how much elastic potential energy
kow [346]

The Potential energy stored in the system is 1 J

<u>Explanation:</u>

Given-

Mass, m = 4 kg

Spring constant, k = 800 N/m

Distance, x = 5cm = 0.05m

Potential energy, U = ?

We know,

Change in potential energy is equal to the work done.

So,

U = \frac{1}{2} k (x)^2\\\\

By plugging in the values we get,

U = \frac{1}{2} * 800 * (0.05)^2\\ \\U = 400 * 0.0025\\\\U = 1J\\

Therefore, Potential energy stored in the system is 1 J

8 0
3 years ago
Sound will travel slowest through which medium?
xxMikexx [17]
Ice at -25
Hope this helps
May God bless you and your family
8 0
3 years ago
A car accelerates for 10 seconds. During this time, the angular
bagirrra123 [75]

Answer:

the angular acceleration of the car is 1.5 rad/s²

Explanation:

Given;

initial angular velocity, \omega_i = 10 rad/s

final angular velocity, \omega_f = 25 rad/s

time of motion, t = 10 s

The angular acceleration of the car is calculated as follows;

a_r = \frac{\omega_f - \omega_i }{t} \\\\a_r = \frac{25-10}{10} = 1.5 \ rad/s^2

Therefore, the angular acceleration of the car is 1.5 rad/s²

4 0
3 years ago
Igneous rocks weather more easily than sedimentary rocks.
IrinaK [193]

Answer:

False because igneous rocks are formed from a volcano and sedimentary never move they stay in one spot

7 0
3 years ago
Given that coal used by electric power plants has a heating value of 27.5 million btus metric ton (25 million btus per ton), det
fredd [130]

Answer:

• 36.4 kg of coal.

• 80 pounds of coal.

Explanation:

Using proportionality constant,

Mass of coal = 1,000,000/27,500,000 btus/metric ton

= 0.0364 metric tons of coal

Mass of coal = 1,000,000/25,000,000 btus/ton

= 0.04 tons of coal.

Converting metric tons to kilogram,

1 metric ton = 1000kg,

0.0364 metric ton;

= 36.4 kg of coal.

Converting tons to pounds,

1 ton = 2000 pounds,

0.04 metric ton;

= 80 pounds of coal.

3 0
3 years ago
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