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2 years ago

15

a slender rod of mass m and length l is released from rest in a horizontal position. what is the rod's angular velocity when it

has rotated through 90

1 answer:

Makovka662 [10]2 years ago

8 0

Answer:

M g H / 2 = M g L / 2 initial potential energy of rod

I ω^2 / 2 = 1/3 M L^2 * ω^2 / 2 kinetic energy attained by rod

M g L / 2 = 1/3 M L^2 * ω^2 / 2

g = 3 L ω^2

ω = (g / (3 L))^1/2

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Which factors effect floridas climate

pishuonlain [190]

Close proximity to the equator leads to very mild winters. Hotter climate year round and snow being extremely rare

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3 years ago

The player who is serving continues to serve until he/she or their team commits a fault.

Roman55 [17]

Answer:

true

Explanation:

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3 years ago

Two points charge of 4\mu C and 2\mu C are placed at theopposite corners of a rectangle. What is the potential difference Va- Vb

bulgar [2K]

Answer:

$Va-Vb=168KV$

Explanation:

From the question we are told that

Two points charge of 4\mu C and 2\mu C

Generally we find the Va and Vb individually to find there difference

Given a rectangle with two equal sides each,Assume lengths for bot sides

Length L=0.3

Breath B=0.4

Diagonal D= $\sqrt{0.3^2+0.4^2} =0.5$

at opposite sides

Mathematically Va can represented as

$Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )$

$Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )$

$Va =9*10^9(0.00001333333-0.000004} )$

$Va =84000V$

$Va =84KV$

Mathematically Vb is represented as

$Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )$

$Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )$

$Va =9*10^9(-0.00001333333+0.000004} )$

$Va =-84000V$

$Va =-84KV$

Therefore

$Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV$

7 0

3 years ago

To test the performance of its tires, a car

VLD [36.1K]

Answer:

0.45

Explanation:

Sum of forces in the y direction:

∑F = ma

N − mg = 0

N = mg

There are friction forces in two directions: centripetal and tangential. The centripetal acceleration is:

ac = v² / r

ac = (31 m/s)² / 333 m

ac = 2.89 m/s²

The total acceleration is:

a = √(ac² + at²)

a = √((2.89 m/s²)² + (3.32 m/s²)²)

a = 4.40 m/s²

Sum of forces:

∑F = ma

Nμ = ma

mgμ = ma

μ = a / g

μ = 4.40 m/s² / 9.8 m/s²

μ = 0.45

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4 years ago

Can an object with acceleration of zero be in motion?

BabaBlast [244]

Answer:

NO

Explanation:

if it has no acceleration then it's not moving

3 0

3 years ago

Read 2 more answers