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1 year ago

15

a slender rod of mass m and length l is released from rest in a horizontal position. what is the rod's angular velocity when it

has rotated through 90

1 answer:

Makovka662 [10]1 year ago

8 0

Answer:

M g H / 2 = M g L / 2 initial potential energy of rod

I ω^2 / 2 = 1/3 M L^2 * ω^2 / 2 kinetic energy attained by rod

M g L / 2 = 1/3 M L^2 * ω^2 / 2

g = 3 L ω^2

ω = (g / (3 L))^1/2

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Read 2 more answers

A 8.8 cm diameter circular loop of wire is in a 1.04 T magnetic field. The loop is removed from the field in 0.30 s . Assume tha

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Answer:

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The average induced emf (E) can be calculated usgin the Faraday's Law:

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<u>Where:</u>

<em>N = is the number of turns = 1 </em>

<em>ΔΦ = ΔB*A </em>

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