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pishuonlain [190]
3 years ago
15

The texture of obsidian is best described as glassy.Why does obsidian contain few or no mineral grains? by the way I put it unde

r physics because that's what it's labeled as on my side.
Physics
1 answer:
Brrunno [24]3 years ago
4 0

hi, so the material that would normally form mineral crystals does not have time to form a crystalline structure because of very rapid cooling after volcanically erupting into the air or onto the surface. Obsidian is a volcanic glass.

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How to determine the amount of resistance when two or more resistors are in parallel.
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Answer: 1/R = 1/R1 + 1/R2+ ...+ 1/Rn

R is resistance of system in which there are resistors R1, R2 , ... Rn parallel.

3 0
3 years ago
Can anyone help me with this? Will give brainliest if correct!
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Answer:

Explanation:

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A uniform plane wave traveling in air is incident upon a flat, lossless, and infinite in extent dielectric interface with a diel
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2 years ago
how does gravity affect objects of different mass close to earth, and how does that effect change as an object moves farther fro
Luda [366]

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It makes it lighter when its closer and heavier when its farther way.

Explanation:

3 0
2 years ago
At a certain instant a particle is moving in the +x direction with momentum +8 kg m/s. During the next 0.13 seconds a constant f
jeka94

Answer:

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

Explanation:

The momentum of the particle is related to force by the following equation:

Δp = F · Δt

Where:

Δp =  change in momentum = final momentum - initial momentum

F = constant force.

Δt = time interval.

Let´s calculate the x-component of the momentum after the 0.13 s:

final momentum - 8 kg m/s = -7 N · 0.13 s

final momentum = -7 kg m/s² · 0.13 s + 8 kg m/s

final momentum = 7.09 kg m/s

Now let´s calculate the y-component of the momentum vector after the 0.13 s. Since the particle wasn´t moving in the y-direction, the initial momentum in this direction is zero:

final momentum = 5 kg m/s² · 0.13 s

final momentum = 0.65 kg m/s

Then, the mometum vector will be as follows:

p = (7.09 kg m/s,  0.65 kg m/s)

The magnitude of this vector is calculated as follows:

|p| = \sqrt{(7.09 kg m/s)^{2} + (0.65 kg m/s)^{2}} = 7.12 kg m/s

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

4 0
3 years ago
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