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agasfer [191]
3 years ago
8

The mass of a fluorine atom is 3.16 × 10 - 23 g. What is the mass of 1,000,000,000 fluorine atoms? express your awnser scientifi

c notation to three significant figures.
Mathematics
1 answer:
elena-s [515]3 years ago
8 0

3.16 × 10 - 23 * 1  x 10 ^ 9 = 3.16 x 10 ^ -14


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Brian made 5 free throws at basketball practice. ethan scored 3 more than twice the number of free throws brian made. which equa
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Lets Brian => b and Ethan => e so
b=5
e=3+2b
will be the equation of finding free throws.

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3 years ago
Can anyone help me with this math?
Gelneren [198K]

Answer:

126

Step-by-step explanation:

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2 years ago
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Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ
const2013 [10]

Answer:

\frac{(2a + 1)^2}{50a}

Step-by-step explanation:

Given

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

Required

Find the equivalent

We start by changing the / to *

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}

Factorize 10a - 5

\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}

Expand 4a² - 1

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: a^2- b^2= (a+b)(a-b)

The expression becomes

\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}

Combine both fractions to form a single fraction

\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}

Divide the numerator and denominator by 2a - 1

\frac{(2a + 1)((2a + 1)}{5*10a}

Simplify the numerator

\frac{(2a + 1)^2}{5*10a}

\frac{(2a + 1)^2}{50a}

Hence,

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1} = \frac{(2a + 1)^2}{50a}

4 0
3 years ago
Question 8 (1 point)
koban [17]

Answer:

PRON

Step-by-step explanation:

FCUCK U

6 0
3 years ago
Solve 7^x-2 =30.
Anna007 [38]

Answer:

x = 3.748

Step-by-step explanation:

this problem requires logs

log_{7} 30 = x-2

x = 2 + log_7 (30) or 3.7479

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2 years ago
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