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Serjik [45]
3 years ago
13

Plz help me in this question

Mathematics
1 answer:
serious [3.7K]3 years ago
6 0

Step-by-step explanation:

option A is correct

as, point S lies on = -7, 4

and point T lies on = 5, 4

so, diameter is 12 so radius = diameter/2 = 12/2 = 6

and center is - 1 , 4 as the diameter lies on 4 in y axis

hope this answer helps you dear...take care and may u have a great day ahead...also may ur exam/test/assignment goes well!.

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Form a polynomial whose real zeros and degree are given.<br> Zeros: – 4, 0, 6;<br> degree: 3
Firdavs [7]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Solve for x. 83 = 35^x Express the answer to the hundredths place (i.e., two digits after the decimal point). x =
devlian [24]

Answer:

x = 1.24

Step-by-step explanation:

In order to get that x down from its current position of exponential, you need to take either the log or the natural log of both sides.  The power rule tells us that we can then pull the exponent down in front.  So let's take the natural log of both sides:

ln(83)=ln(35)^x

We can bring the x down in front to give us:

ln(83) = x ln(35)

The right side of this is "stuck" together by multiplication, so we can undo that multilication by division of the ln(35).  That leaves us with just x on the right:

\frac{ln(83)}{ln(35)}=x

Do this on your calculator and find that x = 1.24

7 0
3 years ago
A pair of equations is shown below:
Nina [5.8K]
Sorry I don't what the answer would be for A. But B would be (3,13)
5 0
3 years ago
Right trapezoid WXYZ is shown. Right trapezoid W X Y Z is shown. Sides X Y and W Z are parallel. Angle W is 73 degrees and angle
cestrela7 [59]

Answer:

∠WXY = 107°

Step-by-step explanation:

In a trapezoid, adjacent angles are supplementary, meaning they add up to 180°. ∠W and ∠WXY are adjacent, so they are supplementary. 180° - 73° = 107°.

Another way to do this is to know that there are 360° in a trapezoid. This is a right trapezoid, so two of the angles are 90°. One angle is 73°. 90° + 90° + 73° = 253°. 360° - 253° = 107°.

I hope this helps :))

8 0
3 years ago
Can someone help me with the first 3 as it is my first time doing it ? <br> I need help
Fed [463]

You problem is you don't have any problem. You have a bunch of formulas for the perimeter and area of some shapes.

As for using the formulas, usually you're given all but one of the variables and you can solve for the remaining one.

Notice how the triangle result doesn't have area as a function of a, b and c. That's called Heron's formula and is usually not taught to secondary school students. I don't like to teach it either because Archimedes' Theorem is so much better:

The sides a,b,c and area S of a triangle satisfy

16S^2 = (a+b+c)(-a+b+c)(a-b+c)(a+b-c) = 4a^2b^2-(c^2-a^2-b^2)^2 = (a^2+b^2+c^2)^2 - 2(a^4+b^4+c^4)

7 0
3 years ago
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