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Stels [109]
3 years ago
8

Why can’t contour lines cross?

Physics
1 answer:
JulsSmile [24]3 years ago
5 0

ANSWER B: A location can only have one elevation.

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An astronaut is taking a space walk near the shuttle when her safety tether breaks. what should the astronaut do to get back to
GuDViN [60]

get hold of some of her equipment, and throw it away from the craft. she should recoil to the craft ... and  hope ???

7 0
2 years ago
A sample of a solid nonmetal is compared to a sample of a solid metal. Both samples have the same volume. What is the most likel
KATRIN_1 [288]
The weight could be different, metals have a higher mass than nonmetals, so when occupying the same amount of space, the weight of the metal is far more.
7 0
2 years ago
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Rowenda is stopped on the side of the road. She then starts pedaling her bicycle for 15 seconds. Her final
lukranit [14]

Explanation:

acceleration = change in velocity / change in time

a = v2-v1

- - - - - -

t

V1 = 0 ( since she stopped)

V2 = 9 m/s

t =15s

a = 9 - 0

- - - -

15

= 0.6m/s^2

5 0
3 years ago
Question 2 (ID=81813)
zaharov [31]

Answer:

The answer is B

Explanation:

5/2=2.5

2.5x2=5

Hope this helps ik its kinda confusing lol

7 0
2 years ago
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A submarine is stranded on the bottom of the ocean with its hatch 21.0 m below the surface. calculate the force (in n) needed to
Tanzania [10]

Answer:

28,400 N

Explanation:

Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:

p_{top} = p_{atm} + \rho g h=1.013\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(21.0 m)=3.071 \cdot 10^5 Pa

On the lower part of the hatch, there is a pressure equal to

p_{bot}=p_{atm}=1.013\cdot 10^5 Pa

So, the net pressure acting on the hatch is

p=p_{top}-p_{bot}=3.071 \cdot 10^5 Pa - 1.013\cdot 10^5 Pa=2.058 \cdot 10^5 Pa

which acts from above.

The area of the hatch is given by:

A=\pi r^2 = \pi (\frac{0.420 m}{2})^2=0.138 m^2

So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch:

F=pA=(2.058\cdot 10^5 Pa)(0.138 m^2)=28,400 N

8 0
3 years ago
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