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Stels [109]
3 years ago
8

Why can’t contour lines cross?

Physics
1 answer:
JulsSmile [24]3 years ago
5 0

ANSWER B: A location can only have one elevation.

You might be interested in
What is the acceleration of a 0.30-kg volleyball when a player uses a force of 42 N to spike the ball?
quester [9]

Answer:

The acceleration will be 140 meter per second

Explanation:

Force F = mass m × acceleration a

If F = 42 N and m = 0.30 kg

Then  acceleration a = F/m

a = 42/0.30

a = 140 m/s

5 0
3 years ago
What is the final concentration of DD at equilibrium if the initial concentrations are [A][A]A_i = 1.00 MM and [B][B]B_i = 2.00
pentagon [3]

Answer:

A) Concentration of A left at equilibrium of we started the reaction with [A] = 2.00 M and [B] = 2.00 M is 0.55 M.

B) Final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M is 0.90 M.

[D] = 0.90 M

Explanation:

With the first assumption that the volume of reacting mixture doesn't change throughout the reaction.

This allows us to use concentration in mol/L interchangeably with number of moles in stoichiometric calculations.

- The first attached image contains the correct question.

- The solution to part A is presented in the second attached image.

- The solution to part B is presented in the third attached image.

8 0
3 years ago
What is the magnitude of the resultant of a 7.0-N force acting vertically upward and a 5.0-N force acting horizontally.
irakobra [83]

Answer:

Resultant force = 8.6N

Explanation:

Using Pythogorus' theorem

{a}^{2}  +  {b}^{2}  =  {c }^{2}  \\  {7}^{2}  +  {5}^{2}  =  {r}^{2} \\ 49 + 25 =  {r}^{2}  \\ 74 =  {r}^{2}  \\   \sqrt{74}  =   \sqrt{ {r }^{2} }  \\ 8.6 = r \\

Resultant force = 8.6N

6 0
2 years ago
How long does a lunar eclipse last? A)seconds B)Minutes C)Days D) Weeks
bonufazy [111]
Well, it happens a few weeks ahead, then for a total of 3 hours and 40 minutes.
3 0
3 years ago
A 30.0 kg box hangs from a rope. What is the tension (in N) in the rope if the box has an initial velocity of 2.0 m/s and is slo
hjlf

Answer:

360 N

Explanation:

m = 30kg    u = 2 m/s     a = -2m/s/s

Since the object has an initial velocity of 2 m/s and acceleration of -2 m/s/s

the object will come to rest in 1 second but the force applied in that one second can be calculated by:

F = ma

F = 30 * -2

F = -60 N (the negative sign tells us that the force is acting downwards)

Now, calculating the force applied on the box due to gravity

letting g = -10m/s/s

F = ma

F = 30 * -10

F = -300 N (the negative sign tells us that the force is acting downwards)

Now, calculating the total downward force:

-300 + (-60) = -360 N

<em></em>

<em>Hence, a downward force of 360 N is being applied on the box and since the box did not disconnect from the rope, the rope applied the same amount of force in the opposite direction</em>

Therefore tension on the force = <u>360 N</u>

5 0
3 years ago
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