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kirill115 [55]
3 years ago
11

On a farm, you are pushing on a stubborn pig with a constant horizontal force with magnitude 30.0 n and direction 37.0° counterc

lockwise from the +x-axis. how much work does this force do during a displacement of the pig that is (a) s s = 15.00 m2nd; (b) s s = ?16.00 m2ne; (c) s s = ?12.00 m2nd + 14.00 m2ne?
Physics
1 answer:
sashaice [31]3 years ago
8 0

<span>Since the force is applied at an angle from the horizontal, we will use the horizontal component of this force in calculating for the displacements.
From derivation, the Fx is:</span>

Fx = F cos φ

Where:

Fx = is the horizontal component of the force

F = total force

φ = angle in radian = 37 * pi / 180 = 0.645 rad

Calculating: Fx = 30.0 N * cos(0.645)

Fx = 23.97 N = 24 N

Calculating for Work: W = Fx * d

A. W = 24 N * 15 m = 360 N

B. W = 24 N * 16 m = 384 N

C. W = 24 N * 12 m = 288 N

D. W = 24 N * 14 m = 336 N 

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Here,

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Two blocks, stacked one on top of the other, slide on a frictionless horizontal surface. The surface between the two blocks is r
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a = 4.905 m/s^2

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two soccer players run toward each other. one player has a mass of 85 kg and runs west with a speed of 8 m/s, while the other ha
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Answer:

Total momentum, p = 55 kg-m/s

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Mass of player 2, m₂ = 105 kg

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Speed of player 2, v₂ = 7 m/s (east)

Momentum is equal to the product of mass and velocity. For this system, momentum is given by :

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8 0
3 years ago
Read 2 more answers
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