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Digiron [165]
3 years ago
11

The acceleration of a car is 10m/s².if the starts from rest , what will be its speed after 10sec.​

Physics
1 answer:
Ivan3 years ago
4 0

Answer:

v = 100 m/s

Explanation:

Given:

v₀ = 0 m/s

a = 10 m/s²

t = 10 s

Find: v

v = at + v₀

v = (10 m/s²) (10 s) + 0 m/s

v = 100 m/s

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A particle of mass 10 g and charge 80 mC moves through a uniform magnetic field,in a region where the free-fall acceleration is .
Alex777 [14]

Answer:

B=1.223\frac{T\cdot m}{s}\frac{1}{v}

Explanation:

According to the first Newton's law, when a particle moves with constant velocity, the sum of forces on it is zero. So, we have:

F_m=F_g

Here F_m=qvBsin\theta is the magnetic force and F_g=mg is the gravitational force. The velocity of the particle is perpendicular to the magnetic field, so \theta=90^\circ. Replacing and solving for B:

qvBsin(90^\circ)=mg\\B=\frac{mg}{qv}\\B=\frac{mg}{q}\frac{1}{v}\\B=\frac{(10*10^{-3}kg)(9.8\frac{m}{s^2})}{80*10^{-3}C}\frac{1}{v}\\B=1.223\frac{T\cdot m}{s}\frac{1}{v}

4 0
3 years ago
A ballast is dropped from a stationary hot-air balloon that is at an altitude of 576 ft. Find (a) an expression for the altitude
Nadya [2.5K]

Answer:

<h2>a) S = \frac{1}{2}gt^2\\</h2><h2>b) 6secs</h2><h2>c) 192ft</h2>

Explanation:

If a ball dropped from a stationary hot-air balloon that is at an altitude of 576 ft, an expression for the altitude of the ballast after t seconds can be expressed using the equation of motion;

S = ut + \frac{1}{2}at^{2}

S is the altitude of the ballest

u is the initial velocity

a is the acceleration of the body

t is the time taken to strike the ground

Since the body is dropped from a stationary air balloon, the initial velocity u will be zero i.e u = 0m/s

Also, since the ballast is dropped from a stationary hot-air balloon, the body is under the influence of gravity, the acceleration will become acceleration due to gravity i.e a = +g

Substituting this values into the equation of the motion;

S = 0 + \frac{1}{2}gt^2\\ S = \frac{1}{2}gt^2\\

a) An expression for the altitude of the ballast after t seconds is therefore

S = \frac{1}{2}gt^2\\

b) Given S = 576ft and g = 32ft/s², substituting this into the formula in (a);

576 = \frac{1}{2}(32)t^2\\\\\\576*2 = 32t^2\\1152 = 32t^2\\t^2 = \frac{1152}{32} \\t^2 = 36\\t = \sqrt{36}\\ t = 6.0secs

This means that the ballast strikes the ground after 6secs

c) To get the velocity when it strikes the ground, we will use the equation of motion v = u + gt.

v = 0 + 32(6)

v = 192ft

7 0
3 years ago
A 0.40 kg object is attached to a spring with force constant 157 N/m so that the object is allowed to move on a horizontal frict
nirvana33 [79]

Answer:

Part a)

F = 26.7 N

Part b)

a = 66.7 m/s^2

Explanation:

Part a)

Force on the object due to spring force is given as

F = kx

here we know that

k = 157 N/m

x = 0.17 m

so we have

F = 157\times 0.17

F = 26.7 N

Part b)

Acceleration of the object is given as

a = \frac{F}{m}

a = \frac{26.7}{0.40}

a = 66.7 m/s^2

8 0
3 years ago
Which process changes substances into new substances with new properties?
Y_Kistochka [10]

Answer:

The answer to your question is: Chemical change

Explanation:

Chemical Change  is a change where substances change their properties because new substances are obtain. This is the right answer.

Compressibility is a property in which a substance is compressed but it continous being the being so this answer is wrong.

Malleability  is a property in whcih substances are flattened into thin sheets but they don't change their properties. This answer is wrong.

Physical Change is a change in which a substance changes its physical state but the properties are the same than the original substance, this answer is wrong.

4 0
3 years ago
Read 2 more answers
Is an electron cloud bigger than an atom?
Rashid [163]

Answer:

no

Explanation:

An electron is one of the components of an atom, so it cannot be larger than that.

5 0
2 years ago
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