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Harman [31]
3 years ago
10

Can a pentagon have angles that measure 95°, 67°, 105°, 95°, and 177°?

Mathematics
1 answer:
pochemuha3 years ago
7 0

Answer:

No, it cannot have angles that measure 95°, 67°, 105°, 95°, and 177°.

Step-by-step explanation:

S = (n-2) * 180

A pentagon has 5 sides, so substitute n for sides (n = 5)

s = 5-2) * 180 = 540°

95° +  67° + 105° + 95° + 177° = 539°

Hope that Helps!

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Answer:

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Step-by-step explanation:

Factorize: (2a - b)² - (a - 2b)²​

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(2a - b)² - (a - 2b)²​ = [(2a - b) + (a - 2b)] × [(2a - b) - (a - 2b)]

1. Distribute and Simplify:

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We now have:

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(3a - 3b) → 3(a - b)

3. Add "(a + b)" back into your factored expression:

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