Answer:
Explanation:
Given:
- mass of the first ball,
- initial velocity of the first ball,
- mass of the second ball,
- initial velocity of the second ball,
- Final velocity of the first ball,
<u>Using the law of conservation of linear momentum:</u>
where: final velocity of the second ball
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<u>Now the kinetic energy lost in the collision:</u>
Δ KE = (Sum of initial individual kinetic energy) - (Sum of individual final kinetic energy)
To solve this problem we will apply the principle of conservation of energy and the definition of kinematic energy as half the product between mass and squared velocity. So,
Here,
m = Mass
V = Velocity
Replacing,
Therefore the final kinetic energy of the two car system is 72.6kJ
To solve this problem we will apply the concept of magnification, which is given as the relationship between the focal length of the eyepieces and the focal length of the objective. This relationship can be expressed mathematically as,
Here,
= Magnification
= Focal length eyepieces
= Focal length of the Objective
Rearranging to find the focal length of the objective
Replacing with our values
Therefore the focal length of th eobjective lenses is 27.75cm
Answer:
Answered
Explanation:
Damping by inert gas is directly proportional to the molecular mass of inert gas.
Damping by inert gas is inversely proportional to the specific heat. One should consider specific heat at constant volume here as pressure will be varying. Since molecular mass is constant, the height of peak will be reduced proportional to the molecular mass.
There is an increase in temperature during detonation of pressure.
Increase in temperature difference, decreases the specific heat and therefore increases the damping.
Answer:
7.2 x 10⁻⁶N
Explanation:
Given parameters:
Mass of Venus = 4.87 x 10²⁴kg
Radius = 6.05 x 10⁶km = 6.05 x 10⁹m
Mass of person = 81kg
Unknown:
Gravitational force = ?
Solution:
To solve this problem, we use the Newtons law of universal gravitation:
Fg =
G is the universal gravitation constant = 6.67 x 10⁻¹¹
Fg =
Fg = 7.2 x 10⁻⁶N