Answer:
speed is -20.0155 m/s
and direction is downward
Explanation:
given data
mass of rocket = 1500 kg
rocket accelerates upward = 10 m/s²
time t = 2 s
maximum height = 530 m
to find out
speed and direction of the heavier fragment just after the explosion
solution
we use here principle of conservation of momentum that is
Mt Vt=M1 V1 + M2 V2 ................1
so here
first we find the initial velocity that is express as
v = a × t .....................2
v = 10 × 2
v = 20 m/s
and distance S
S =u × t + 0.5 × a × t² ...................3
S = 0 + 0.5 × 10 × 2²
S = 20 m
and now we find speed of the lighter piece that is
v² = v1² + 2 × a × S .................4
0 = v1² + 2 × -9.81 × (530-20)
v1² = 10006.2
v1 = 100.031 m/s
so now put all these in equation 1 we get
Mt Vt = M1 V1 + M2 V2
1500 × 20 = (1500 × 1/3 ) × 100.031 + (1500 × 2/3) + V2
30000 = 50015.5 + 1000 V2
V2 = -20.0155 m/s
so speed is -20.0155 m/s
that mean vertical component of second fragment will be move downward
The true statement according to Newton's laws of motion is; "there is no net force on the block during the 2nd second as zero net force keeps the motion constant."
According to the Newton first law of motion, an object will continue in its state of rest or uniform motion unless it is acted upon by a net force. The action of a net force leads to an acceleration.
In the 2nd second of the journey, there is no net force on the block hence the block continues to move at constant velocity.
Learn more: brainly.com/question/13678295
Temperature: Higher temperatures increase the energy and therefore the movement of the molecules, increasing the rate of diffusion. Lower temperatures decrease the energy of the molecules, thus decreasing the rate of diffusion. Solvent density: As the density of a solvent increases, the rate of diffusion decreases.
I did try to solve. I hope it is correct, below is the solution:
<span>put everything in s.i units
then the answer what u wrote is acceleration to get is divide by mass(80)
G=6.011*10^-11
M=6*10^24
R=6.4*10^6
m=80
</span>
Hope it helps.