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Mice21 [21]
4 years ago
10

Q.3 There is two conductors A and B of same

Physics
2 answers:
babymother [125]4 years ago
7 0
The resistance is proportional to the length and inversely proportional to the area (which is proportional to the square of the radius). Thus if we are just comparing the two (so the constants will cancel out).

r1 = l/r^2 (r squared).

r2 = (2l)/(1/2r)^2

r2 = 2l/(1/4)r^2

dividing by 1/4 is the same as multiplying to 4, so you are multiplying by 2 and then by 4, thus by 8.

Thus R2 is 8 times more than R1
Viktor [21]4 years ago
5 0

Answer:

resistance = (resistivity.(l/A))

so for the 2 materials we get

r1 = resistivity.(l/r)

r2=resistivity.(2l/(r/2))

so ratio r1/r2=1/4

Explanation:

The resistance is proportional to the length and inversely proportional to the area (which is proportional to the square of the radius). Thus if we are just comparing the two (so the constants will cancel out).

r1 = l/r^2 (r squared).

r2 = (2l)/(1/2r)^2

r2 = 2l/(1/4)r^2

dividing by 1/4 is the same as multiplying to 4, so you are multiplying by 2 and then by 4, thus by 8.

Thus R2 is 8 times more than R1.

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A researcher is interested in determining the average length and weight of loblolly pine tree needles in the southeast United St
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Answer:

Experimentation

Explanation:

The loblolly pine tree is a member of the yellow pine group which is grown in plantations for commercial production of timber.The tree itself can reach a height of 40 meters with a truck of 1 meter in diameter.Pines have long needle-like leaves held in bundles. A researcher can measure the length of the needles, count the number of needles in a bundle, and measure the length of the sheath.Loblloly pine needles measure up to 17 cm long.The researcher can also weigh a bundle and determine the weight of the needles.This is field experiment that will require a measuring device for weight and length so observation alone won't provide the needed data.

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3 years ago
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Within any ecosystem, there is a fixed amount of energy available for organisms to use. Since organisms usually produce more off
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I'm going to say carrying capacity since carrying capacity is the maximum amount of organisms that can live in an ecosystem. So the reason for there being a maximum of organisms is because, like the question says, organisms usually produce more offspring than the ecosystem can support.
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3 years ago
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A rocket starts from rest and moves upward from the surface of the earth. For the first 10s of its motion, the vertical accelera
Naily [24]
Since the rocket’s acceleration is 3.00 m/s^3 * t, its acceleration is increasing at the rate of 3 m/s^3 each second. The equation for its velocity at a specific time is the integral of the acceleration equation. 

<span>vf = vi + 1.5 * t^2, vi = 0 </span>
<span>vf = 1.5 * 10^2 = 150 m/s </span>
This is the rocket’s velocity at 10 seconds. The equation for its height at specific time is the integral velocity equation

<span>yf = yi + 0.5 * t^3, yi = 0 </span>
<span>yf = 0.5 * 10^3 = 500 meters </span>
<span>This is the rocket’s height at 10 seconds. </span>

<span>Part B </span>
<span>What is the speed of the rocket when it is 345 m above the surface of the earth? </span>
<span>Express your answer with the appropriate units. </span>


<span>Use the equation above to determine the time. </span>

<span>345 = 0.5 * t^3 </span>
<span>t^3 = 690 </span>
<span>t = 690^⅓ </span>
<span>This is approximately 8.837 seconds. Use the following equation to determine the velocity at this time. </span>

<span>v = 1.5 * t^2 = 1.5 * (690^⅓)^2 </span>
<span>This is approximately 117 m/s. </span>


<span>The graph of height versus time is the graph of a cubic function. The graph of velocity is a parabola. The graph of acceleration versus time is line. The slope of the line is the coefficient of t. This is a very different type of problem. For the acceleration to increase, the force must be increasing. To see what this feels like slowly push the accelerator pedal of a car to the floor. Just don’t do this so long that your car is speeding!!</span>
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When does a nebula become a star?
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7 0
4 years ago
600 kg elephant runs at 5 m/s and jumpts onto a 100kg cart. If the coefficient of friction is .04 how far will the cart travel o
Minchanka [31]

Answer:

Eleven seconds.

Explanation:

Two keys are needed to solve this problem. First, the conservation of momentum: allowing you to calculate the cart's speed after the elephant jumped onto it. It holds that:

m_ev_e+m_c\cdot0=(m_e+m_c)v_0\implies \\v_0=\frac{m_ev_e}{m_e+m_c}=\frac{600kg\cdot 5\frac{m}{s}}{700kg}=4.29\frac{m}{s}

So, once loaded with an elephant, the cart was moving with a speed of 4.29m/s.

The second key is the kinematic equation for accelerated motion. There is one force acting on the cart, namely friction. The friction acts in the opposite direction to the horizontal direction of the velocity v0, its magnitude and the corresponding deceleration are:

F_r = 0.04\cdot (m_e+m_c)g\implies a_r = 0.04\cdot g= 0.04 \cdot 9.8 \frac{m}{s^2}=0.39\frac{m}{s^2}

The kinematic equation describing the decelerated motion is:

v = -a_r t+v_0\\0 = -a_rt+v_0\implies \\t = \frac{v_0}{a_r}=\frac{4.29\frac{m}{s}}{0.39\frac{m}{s^2}}=11s

It takes 11 seconds for the comical elephant-cart system to come to a halt.

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