Answer:
if ∠Q=∠R
draw an angular bisector from P to QR in which it intersect wit Qr at point S
now we have two triangle : QPS and RSP
in which angle : QPS=RPS ( PS is angular bisector)
and we have angle Q and angle R are equal
and PS is common side
this makes triangle QPS and RSP are congruent by AAS(angle angle side)
which also means that pQ=PR ( proved)
Answer:
The ratio of the lateral sides and perimeters = the ratio of square root of their areas
Then, the ratio of the sides and the perimeters is 6:5 or if this is wrong it it is 5:6
if this helps plz mark as brainliest
B don’t quote me if I’m wrong
Answer:
angle 1= 70 degrees
angle 2= 65 degrees
angle 3= 65 degrees
angle 4 = 115 degrees
angle 5= 45 degrees
angle 6= 45 degrees
angle 7= 45 degrees
Step-by-step explanation:
